Answer:
2 NaOH + H2SO4 2 H2O + Na2SO4
How many grams of sodium sulfate will be formed if you start with 200.0
grams of sodium hydroxide and you have an excess of sulfuric acid?
355.3 grams of Na2SO4
200.0 g NaOH 1 mol NaOH 1 mol Na2SO4 142.1 g Na2SO4
40.00 g NaOH 2 mol NaOH 1 mol Na2SO4
= 355.3 g
Explanation:
First we must write a balanced chemical equation for this reaction

The mole ratio for the reaction between
and
is 1:2. This means 1 moles of
will neutralize 2 moles
. Now we find the moles of each reactant based on the mass and molar mass.



The
was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.
Answer:
This flexible ability is important because it allows the cell to survive in differing environments, such as when immersed in water over long periods of time.