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andrey2020 [161]
3 years ago
5

Jessica Jacob is driving down the road at 35 m/s. She sees a cop and slows to 20 m/s in only 2 seconds. What was her acceleratio

n?
Physics
1 answer:
kati45 [8]3 years ago
8 0

Answer: Acceleration = - 7.5 m/s^2

Explanation:

Acceleration (a) is the rate of change in velocity. I.e

Acceleration = (V - U)/t

U = 35 m/s

V = 20 m/a

t = 2 s

Acceleration = ( 20 - 35 )/2

Acceleration = - 15/2

Acceleration = - 7.5 m/s^2

In this case, the car is decelerating at 7.5 m/s^2

You might be interested in
A soccer ball with a mass of 0.45 kg is kicked and is moving at 8.9 m/s. Find the kinetic
strojnjashka [21]

Answer:

17.82J

Explanation:

Kinetic energy = 1/2 mv^2

Given

Mass M = 0.45kg

Velocity v = 8.9m/s

Therefore,

K.E. = 1/2 x 0.45 x (8.9)^2

= 1/2 x 0.45 x (8.9 x 8.9)

= 1/2 x 0.45 x 79.21

Multiply through

= 35.6445/2

= 17.82J

The kinetic energy of the ball is 17.82J

3 0
2 years ago
If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is
navik [9.2K]

Answer:

15 and Increasing

Explanation:

Hope this helps

Have a wonderful day and many more to come

Alexis~

~A.K.A Moon~

7 0
2 years ago
A disk is uniformly accelerated from rest with angular acceleration α. The magnitude of the linear acceleration of a point on th
solniwko [45]

Answer:

a = R\alpha\sqrt{1 + \alpha^2t^4}

Explanation:

As we know that the acceleration of a point on the rim of the disc is in two directions

1) tangential acceleration which is given as

a_t = R\alpha

2) Centripetal acceleration

a_c = \omega^2 R

here we know that

\omega = \alpha t

a_c = (\alpha t)^2 R

now we know that net linear acceleration is given as

a = \sqrt{a_c^2 + a_t^2}

so we have

a = \sqrt{R^2\alpha^2 + R^2(\alpha t)^4}

a = R\alpha\sqrt{1 + \alpha^2t^4}

4 0
2 years ago
A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete on
riadik2000 [5.3K]

Answer:

Explanation:

14

8 0
2 years ago
1. Mr. Ure has a mass of 65 kg, due to the fact that he is WAY too skinny! What is the force of Earth's gravity on him?
shepuryov [24]

1.

m = mass of Mr. Ure = 65 kg

g = acceleration due to gravity = 9.8 m/s²

force of earth's gravity on Mr. Ure is given as

F = mg

F = 65 x 9.8

F = 637 N


2.

F = force of gravity on car = 3050 N

m = mass of the car = ?

g = acceleration due to gravity = 9.8 m/s²

force of gravity on car is given as

F = mg

3050 = m (9.8)

m = 3050/9.8

m = 311.22 kg


3.

m = mass of Mr. Rees = 90 kg

g = acceleration due to gravity = 9.8 m/s²

force of earth's gravity on Mr. Rees is given as

F = mg

F = 90 x 9.8

F = 882 N


7 0
3 years ago
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