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photoshop1234 [79]
2 years ago
5

Which product of respiration is used for tissue repair and cellular function?

Chemistry
2 answers:
I am Lyosha [343]2 years ago
8 0

Answer:

carbon dioxide

Explanation:remember to make mi brainliest

maxonik [38]2 years ago
7 0
Answer :
Carbon Dioxide
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In water, what happens to a base?
BartSMP [9]
A base in water will form hydroxide ions. This is because bases are AOH while acids are AH+. I hope this helps!
5 0
3 years ago
PlEASE HELP! 40!
podryga [215]

Answer:

moles Na = 0.1114 g / 22.9898 g/mol=0.004846

moles Tc = 0.4562g /98.9063 g/mol=0.004612

mass O = 0.8961 - ( 0.1114 + 0.4562)=03285 g

moles O = 0.3285 g/ 15.999 g/mol=0.02053

divide by the smallest

0.02053/ 0.004612 =4.45 => O

0.004846/ 0.004612 = 1.0 => Tc

to get whole numbers multiply by 2

Na2Tc2O 9

Explanation:

Hope it right hope it helps

5 0
2 years ago
Is the electrochemical cell spontaneous or not spontaneous as written at 25 ∘C ? spontaneous not spontaneous Calculate the poten
givi [52]

Answer:

The cell potential is 0.609 V. Given E > 0 the electrochemical cell is spontaneous as written.

Explanation:

Let's consider the oxidation and reduction half-reactions and the global reaction.

Anode (oxidation): Sn²⁺(0.0023 M) ⇒ Sn⁴⁺(0.13 M) + 2 e⁻

Cathode (reduction): 2 Fe³⁺(0.11 M) + 2 e⁻ ⇒ 2 Fe²⁺(0.0037 M)

Global reaction: Sn²⁺(0.0023 M) + 2 Fe³⁺(0.11 M) ⇒ Sn⁴⁺(0.13 M) + 2 Fe²⁺(0.0037 M)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red,cat - E°red,an

E° = 0.771 V - 0.154 V = 0.617 V

The Nernst equation allows us to calculate the cell potential (E) under the given conditions.

E=E\° -\frac{0.05916}{n} logQ\\E=E\° -\frac{0.05916}{n} log\frac{[Sn^{+4}].[Fe^{2+}]}{[Sn^{2+}].[Fe^{3+} ]} \\E=0.617V-\frac{0.05916}{2} log\frac{(0.13).(0.0037)}{(0.0023).(0.11)} \\E=0.609V

The cell potential is 0.609 V. Given E > 0 the electrochemical cell is spontaneous as written.

4 0
3 years ago
Identify the independent variable and the dependent variable in each of the following hypothesis.
nlexa [21]

Answer:

independent variable is the carbon dioxide

dependent variable is the rate of photosynthesis.

Explanation:

4 0
3 years ago
An 8.42 g piece of metal with a specific heat of 1.020 J g-1 k-1 wasn't heated to an unknown temperature. The metal was then pla
ANTONII [103]

Answer:

T = 61.344\,^{\textdegree}C

Explanation:

The heat received by water is equal to the heat rejected by the piece of metal. That is to say:

-Q_{piece} = Q_{water}

(8.42\,g) \cdot \left(1.020\,\frac{J}{g\cdot ^{\textdegree}C}  \right) \cdot (T - 20.40\,^{\textdegree}C)= (44.2\,g)\cdot \left(4.187\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (20.40\,^{\textdegree}C-18.50\,^{\textdegree}C)

\left(8.588\,\frac{J}{^{\textdegree}C} \right)\cdot (T-20.40\,^{\textdegree}C) = 351.624\,J

The initial temperature of the piece of metal is:

T = 61.344\,^{\textdegree}C

4 0
3 years ago
Read 2 more answers
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