Answer:
0.65 M
Explanation:
Molarity (M) is the amount of moles of a substance per liter.
In other words, M = moles of substance / liters of solution
Since you're already given the moles of NaCl and the volume of the solution, you can plug those into the equation.
M = moles of NaCl / liters of solution
M = 1.5 mol NaCl / 2.3 L
M = 0.65 mol/L (or 0.65 M)
Given:
12.0 M HCl
2.0 liters of a 3.0 M HCl
Required:
volume of concentrated hydrochloric acid
Solution:
M1V1 = M2V2
(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)
V1 = (3.0 M HCl)( 2.0 liters)/ (12.0
M HCl)
V1 = 0.5 liters
<span>Molarity
is expressed as the number of moles of solute per volume of the solution. We solve the problem above as follows:
0.1000 mol Mg(NO3)2 / L (.1 L) ( </span><span>148.3 g / mol ) = 1.483 g Mg(NO3)2
</span>0.1000 mol Sr(NO3)2 / L (.1 L) ( 211.63 g / mol ) = 2.116 g Sr(NO3)2
Hope this answers the question. Have a nice day.
<h3>
Answer:</h3>
Empirical formula is CrO
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of sample of Chromium as 7.337 gram
- Mass of the metal oxide formed as 9.595 g
We are required to determine the empirical formula of the metal oxide.
<h3>Step 1 ; Determine the mass of oxygen used </h3>
Mass of oxygen = Mass of the metal oxide - mass of the metal
= 9.595 g - 7.337 g
= 2.258 g
<h3>Step 2: Determine the moles of chromium and oxygen</h3>
Moles of chromium metal
Molar mass of chromium = 51.996 g/mol
Moles of Chromium = 7.337 g ÷ 51.996 g/mol
= 0.141 moles
Moles of oxygen
Molar mass of oxygen = 16.0 g/mol
Moles of Oxygen = 2.258 g ÷ 16.0 g/mol
= 0.141 moles
<h3>Step 3: Determine the simplest mole number ratio of Chromium to Oxygen</h3>
Mole ratio of Chromium to Oxygen
Cr : O
0.141 mol : 0.141 mol
1 : 1
Empirical formula is the simplest whole number ratio of elements in a compound.
Thus the empirical formula of the metal oxide is CrO
You could try rubbing coconut oil on it with a cloth it should come off
