Answer:
n(t) = 10×1.2^t
Step-by-step explanation:
The idea here is that the number of ill students is multiplied by 1+20% = 1.20 each hour. That is, after t hours, you have multiplied the original number by 1.20 "t" times. Of course, repeated multiplication is signified using an exponent.
The form you can use in such cases is ...
value = (initial value)×(growth factor in period)^(number of periods)
Here, you're given a growth rate (20% per hour), so you add 1 to get the growth factor (as we showed above).
Your exponential function can be ...
n(t) = 10×1.20^t
<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect'
fifth apart are in the ratio of 1.5
i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5
Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99
Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz
16 to 18 simplifies down to 8 to 9 because you divide 2 to both terms
24 to 27 simplifies down to 8 to 9 because you divide 3 to both terms
So yes
A
Answer:
Step-by-step explanation:
3x^2 - x + 2x^2 + 3x = 5x^2 + 2x
