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aliina [53]
3 years ago
11

The conversion of cyclopropane to propene in the gas phase is a first-order reaction with a rate constant of 6.7 x 10-4 s -1 at

500 C. Cyclopropane (CH2CH2CH2) -- CH3-CH=CH2 (propene) If the initial concentration of the reactant was 0.25 M, what is the concentration after 8.8 min?
Chemistry
1 answer:
denpristay [2]3 years ago
8 0

Answer:

C_f=0.1755M

Explanation:

Hello,

Based on the information and the units of the given data, the integrated rate law turns out into:

\frac{dC}{dt}=-kC\\ C_f=C_0exp(-kt)\\C_f=0.25M*exp(-6.7x10^{-4}s^{-1}*8.8min*\frac{60s}{1min} )\\C_f=0.1755M

Best regards.

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6 0
3 years ago
How many moles of water are needed to produce 56.8 g C2H2?
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2 years ago
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olya-2409 [2.1K]

Answer:

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Explanation:

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4 0
3 years ago
If 200. mL of 0.60 M MgCl2(aq) is added to 400 mL of distilled water, what is the concentration of Mg and Cl in the resulting so
sladkih [1.3K]

Answer:

C. 0.20 M Mg ion & 0.40 M Cl ion

Explanation:

MgCl₂ is a ionic salt which is dissociated as this

MgCl₂  →  Mg²⁺  +  2Cl⁻

First of all, we have a solution of 200 mL, with [MgCl₂] = 0.6M

Molarity . volume = moles.

0.6 mol/l . 0.2l = 0.12 mol

  MgCl₂  →  Mg²⁺  +  2Cl⁻

0.12mol      0.12         0.24

This moles are also in 400mL of water, so the new concentration is

[Mg²⁺] = 0.12 m/0.6L = 0.2M

[Cl⁻] = 0.24 m/0.6L = 0.4M

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8 0
2 years ago
A gas at 29.4 kPa is cooled from a temperature of 75°C to a temperature of 25°C at constant volume. What is the new pressure of
kirill115 [55]

<span>To solve this we assume that the gas inside the balloon is an ideal </span>gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant volume pressure and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

 

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 25 x 29.4 / 75

P2 = 9.8 kPa

7 0
3 years ago
Read 2 more answers
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