The conversion of cyclopropane to propene in the gas phase is a first-order reaction with a rate constant of 6.7 x 10-4 s -1 at

Question

3 years ago

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The conversion of cyclopropane to propene in the gas phase is a first-order reaction with a rate constant of 6.7 x 10-4 s -1 at

500 C. Cyclopropane (CH2CH2CH2) -- CH3-CH=CH2 (propene) If the initial concentration of the reactant was 0.25 M, what is the concentration after 8.8 min?

Chemistry

1 answer:

denpristay [2] · Answer 1 · 2022-03-12T13:47:38+03:00

denpristay [2]3 years ago

8 0

Answer:

$C_f=0.1755M$

Explanation:

Hello,

Based on the information and the units of the given data, the integrated rate law turns out into:

$\frac{dC}{dt}=-kC\\ C_f=C_0exp(-kt)\\C_f=0.25M*exp(-6.7x10^{-4}s^{-1}*8.8min*\frac{60s}{1min} )\\C_f=0.1755M$

Best regards.