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boyakko [2]
3 years ago
14

A rifle of mass 2 kg is suspended by strings. The rifle fires a bullet of mass 0.01 kg at a speed of 200 m/s. The recoil velocit

y of the rifle is about ____.
(A) 0.001 m/s.
(B) 0.01 m/s.
(C) 0.1 m/s.
(D) 1 m/s
Physics
1 answer:
ozzi3 years ago
5 0

Answer:

option D  

Explanation:

given,

mass of the rifle,M = 2 Kg

mass of the bullet , m = 0.01 Kg

speed of the bullet, v = 200 m/s

recoil velocity ,v'= ?

initial velocity of bullet and rifle is zero.

using conservation of energy

Mu + m u' = M v'+ m v

0 + 0  = 2 x v' + 0.01 x 200

2 v' = -2

   v' = -1 m/s

negative sign represent the velocity of rifle is in opposite direction of bullet.

hence, the correct answer is option D  

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If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, A)compression B)w
Gnesinka [82]
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Thus, your answer is option B.

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7 0
3 years ago
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A 6.00-kg box sits on a ramp that is inclined at 37.0° above the horizontal. the coefficient of kinetic friction between the box
forsale [732]
We need to see what forces act on the box:

In the x direction:

Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.

In the y direction:

N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force. 

From N-Gcosα=0 we get: 

N=Gcosα, we will need this for the force of friction.

Now to solve for Fh:

Fh=ma + Ff + Gsinα,

Ff=μN=μGcosα, this is the friction force where μ is the coefficient of friction. We put that into the equation for Fh.
G=mg, where m is the mass of the box and g=9.81 m/s²

Fh=ma + μmgcosα+mgsinα

Now we plug in the numbers and get:

Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N

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8 0
3 years ago
Two thousand two hundred frequent business travelers are asked which midwestern city they prefer: Indianapolis, Saint Louis, Chi
drek231 [11]
Frequency Table
City                       Frequency
Indianapolis              124
Saint Louis                416
Chicago                  1,225
Milwaukee                 435

Relative Frequency Table
City                            Relative Frequency
Indianapolis              124/2200 = 31/550
Saint Louis                416/2200 = 52/275
Chicago                  1,225/2200 = 49/88
Milwaukee                 435/2200 = 87/440
5 0
3 years ago
When potential energy ___________ , kinetic energy increases.
BARSIC [14]

When potential energy <u>decreases</u>, kinetic energy increases.

5 0
2 years ago
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The rectangular boat shown below has base dimensions 10.0 cm × 8.0 cm. Each cube has a mass of 40 g, and the liquid in the tank
Paladinen [302]

When boat is sunk into the liquid the net buoyancy on the boat is counterbalanced by weight of the boat

So here weight of the boat = Buoyancy force

let say boat is sunk by distance "h"

now we can say

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F_b = 1000*0.10 * 0.08 * h * 9.8

now by above force balance equation we can write

m*g = F_b

0.040 * 9.8 = 1000 * 0.10 * 0.08 * h * 9.8

0.040 = 8h

h = 5 * 10^{-3} m

so boat will sunk by total 5 mm distance

8 0
3 years ago
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