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alexgriva [62]
2 years ago
6

Because it can go from rest to 14.2 m/s (about 32 mi/h) in 2.1 s, one of the fastest-accelerating animals is the cheetah. If its

mass is 56.0 kg, determine the average power developed by the cheetah during the acceleration phase of its motion. Express your answer in the following units.
(a) watts and
(b) horsepower.
Physics
1 answer:
TEA [102]2 years ago
6 0

Answer:

(a) P_{power}=2688.53Watt

(b) P_{power}=3.605hp

Explanation:

For part (a)

As we know that

P_{power}=\frac{W_{work}}{t_{time}}\\As\\ W=1/2(mv_{f}^{2}-mv_{o}^{2} )So\\P_{power}=\frac{1/2(mv_{f}^{2}-mv_{o}^{2} )}{t}\\ P_{power}=\frac{1/2(56.0kg*(14.2m/s)^2-56.0kg*(0m/s)^2)}{2.1s} \\P_{power}=2688.53Watt

For part (b)

The power in unit of horsepower is:

P_{power}=(2688.53Watt)(\frac{1hp}{745.7Watt} )\\P_{power}=3.605hp

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Answer:

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

Explanation:

The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

         qA = ½ q

         qB = ½ q

         qC = 0

The total charge is q

we make a second contact

If we touch the ball A again with the other sphere not charged C, the chare is distributed and when separated it is reduced by half

         qA = 1/2 (q / 2) = ¼ q

         qC = ¼ q

         qB = ½ q

At this point all spheres have a charge,

      qA = ¼ q

      qb = ½ q

      qC = ¼ q

The total charge is q

Now let's contact spheres B and one of the other two

       Q = ½ q + ¼ q = ¾ q

When splitting the charge

        qB = ½ ¾ q = 3/8 q

        qC = ½ ¾ q = 3/8 q

        qA = ¼ q

The total charge is q

Note that the total load is always equal to q

Now let's analyze the given configuration

Let's look for the total load

       Q = qA + QB + QC

       Q = ½ q + 3/8 q + ¼ q

        Q = 9/8 q

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

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