Answer:
F₂ = -7.3 N
Explanation:
Given that,
The mass of an object, m₁ = 3.7 kg
First force, F₁ = 11 N
The net acceleration of the object is 1 m/s².
We know that,
F₁+F₂ = ma
11+F₂ = (3.7)(1)
F₂ = 3.7-11
F₂ = -7.3 N
so, the other force is 7.3 N and it is acting in west direction.
You can find your answer here www.rsc.org/education/teachers/resources/jesei/minerals/students.htm
Answer:
Option B. Coulomb Repulsion
Explanation:
The reason for the heavy nucleus not being able to follow the trend or the N= Z line is because of the fact that as the atomic number, Z of an atom increases, the number of protons inside the atom also increases. Since the neutrons are charge less particles whereas the protons are positively charged particle and hence as these increases in number there is an increase in the repulsive force between the like charges, i.e., positively charged protons which is Coulomb repulsion.
Answer:
ω = 22.36 Hz
f = 3.56 Hz
T = 0.28 s.
Explanation:
a) The angular frequency (ω), can be calculated using the following equation:
<u>Where:</u>
<em>k: is the spring constant = F/x</em>
<em>m: is the mass of the particle = 0.500 kg</em>
<em>F: is the force applied = 7.50 N </em>
<em>x: is the displacement = 3.00 cm = 0.03 m </em>
Therefore, the angular frequency of the motion is 22.36 Hz.
b) To find the frequency (f) we can use the next equation:
Hence, the frequency of the motion is 3.56 Hz.
c) The period (T) is equal to:
Therefore, the period of the motion is 0.28 s.
I hope it helps you!