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max2010maxim [7]
2 years ago
9

An aluminum alloy tube with an outside diameter of 3.50 in. and a wall thickness of 0.30 in. is used as a 14 ft long column. Ass

ume that E = 10,000 ksi and that pinned connections are used at each end of the column. Determine the slenderness ratio and the Euler buckling load for the column.
Engineering
1 answer:
slega [8]2 years ago
3 0

Answer:

slenderness ratio = 147.8

buckling load = 13.62 kips

Explanation:

Given data:

outside diameter is 3.50 inc

wall thickness 0.30 inc

length of column is 14 ft

E = 10,000 ksi

moment of inertia = \frac{\pi}{64 (D_O^2 -D_i^2)}

I = \frac{\pi}{64}(3.5^2 -2.9^2) = 3.894 in^4

Area = \frac{\pi}{4} (3.5^2 -2.9^2) = 3.015 in^2

radius = \sqrt{\frac{I}{A}}

r = \sqrt{\frac{3.894}{3.015}

r = 1.136 in

slenderness ratio = \frac{L}{r}

                              = \frac{14 *12}{1.136} = 147.8

buckling load = P_cr = \frac{\pi^2 EI}}{l^2}

P_{cr} = \frac{\pi^2 *10,000*3.844}{( 14\times 12)^2}

P_{cr} = 13.62 kips

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Answer and Explanation:

// code

class Main {

   public static void main(String[] args) {

       /*

        *

        *

        * your code

        *

        */

       System.out.println(inDogish("aplderogad"));

       System.out.println(inXish("aplderogad", "dog"));

   }

   // returns true if the word is in dog-ish

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   public static boolean inDogish(String word) {

       // first find d

       if (dogishHelper(word, 'd')) {

           // first find string after d

           String temp = word.substring(word.indexOf("d"));

           // find o

           if (dogishHelper(temp, 'o')) {

               // find string after o

               temp = temp.substring(temp.indexOf("o"));

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The output is attached below

       }

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   }

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}

PS E:\fixer> java Main true true ne on

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