Question

1. Suppose during volleyball practice, you lost 2.0 lbs of water due to sweating. If all of this

Answer 1

Answer:

$E=2052.8 kJ$

Explanation:

The energy absorbed by the water is the energy it requires to evaporate. So:

$Heat of .vap= 40.65 kJ/mol$

The moles of water:

$n_w=m_w *\frac{1000g}{2.2lbs}*\frac{1}{M}$

M is the water molecular weight

$n_w=2 lbs *\frac{1000g}{2.2lbs}*\frac{1}{18g/mol}$

$n_w=50.5mol$

The energy absorbed:

$E=n_w*Heat of vap.=50.5mol *40.65 kJ/mol$

$E=2052.8 kJ$