Convert 12.64 g of NaOH to moles
2 answers:
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Complete Question
The complete question is shown on the first uploaded image
Answer:
a) Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
b) Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
c) The IUPAC name is Butan-2-ol
Explanation:
Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.
According to that for molecule 1 as shown on the second uploaded image
For Proton Ha, number of non equivalent protons n= 2
Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
Considering the second question for Molecule 2 as shown on the third uploaded image
For Proton Ha, number of non equivalent protons n= 1
Splitting pattern for Ha= 1+1=2 , Doublet
For Proton Hb, number of non equivalent protons n= 3
Splitting pattern for Hb= 3+1=4 , Quartet
For Proton Hc, number of non equivalent protons n= 3
Splitting pattern for Hc= 3+1=4 , Quartet
For Proton Hd, number of non equivalent protons n= 1
Splitting pattern for Ha= 1+1=2 , Doublet
Considering the third question
The name of the given molecule is gotten according to longest carbon chain = 4 (Prefix 'Butan')
Functional group = -OH (Suffix 'ol') at C-2
The IUPAC name is Butan-2-ol
Answer:
Option 3. The catalyst does not affect the enthalpy change () of a reaction.
Explanation:
As its name suggests, the enthalpy change of a reaction () is the difference between the enthalpy of the products and the reactants.
On the other hand, a catalyst speeds up a reaction because it provides an alternative reaction pathway from the reactants to the products.
In effect, a catalyst reduces the activation energy of the reaction in both directions. The reactants and products of the reaction won't change. As a result, the difference in their enthalpies won't change, either. That's the same as saying that the enthalpy change of the reaction would stay the same.
Refer to an energy profile diagram. Enthalpy change of the reaction measures the difference between the two horizontal sections. Indeed, the catalyst lowered the height of the peak. However, that did not change the height of each horizontal section or the difference between them. Hence, the enthalpy change of the reaction stayed the same.
