A block of mass mm starts from rest and slides down from the top of a wedge of height hh and length dd. The surface of the wedge
1 answer:
Answer:
Explanation:
Given that
Mass = m
Height = h
Length = d
Angle = θ
Friction force = f
When block slides downward then friction force will act upwards
The force due to gravity along inline plane
Fg= mg sinθ
Lets 'a' is the acceleration
From Newtons law
mg sinθ - f = m a
a= (g sinθ - f/m)
Given that initial speed u= o ,lets v is final speed
v²=u²+ 2 a s
v²=2 x (g sinθ - f/m) x d
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The vertical movement of the projectile is described by:
y = H - gt² / 2
When the cannonball is on the ground, y= 0 so:
0 = H - gt² /2
Solving for t:
The horizontally movement of the projectile is described by:
x = v₀t
Solving for v₀:
v₀ = x/t
v₀ = 175 m / 2.8 s
v₀ = 61.5 m/s