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Arisa [49]
3 years ago
12

SO! I'VE GOT A COUPLE QUESTIONS RELATING TO SCIENCE (WHERE ARE MY SCIENCE WHIZZES?) TRUST ME THERE WILL BE MORE

Physics
2 answers:
Helga [31]3 years ago
5 0

Answer:

nnnnnnnnnnnnnnnnnnnnnnnn

Explanation:

Zigmanuir [339]3 years ago
3 0

Answer:

maybe a

Explanation:

earth has gravity so it would pull to it so it would be a.

tldr;moon moving away earth gravity keeps it in.

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imagine that a tank is filled with water the hight of the liquid column is 7 meters and the area is 1.5 sq meters (m™). what's t
Annette [7]
Answer - 12,900 Newtons

Explanation

First, we find the volume of the water
Volume = Area * Heinght
= 1.5 m² x 7 m
=  10.5 m³
 
Covert the volume to liters
1 m³ of water = 1000  liters
10.5 m³ of water = 10.5 m³ * 1000 liters liter/m³
= 10,500 liters
 
Use the volume of water to calculate the mass
1 liter of water weighs 1 kg
10,500 liters of water = 10,500 * 1 kg/liter
= 10,500 kg
 
Now, we can calculate the force of gravity on the water
Force of gravity on the water = Weight of the water
Weight = Mass * Acceleration
 
Mass = 10,500kg
Acceleration (due to gravity) = 9.8 m/s²

Force of gravity on the water
= Weight of the water
= Mass * Acceleration
= 10,500 kg * 9.8 m/s²
 = 102,900 Newtons 
8 0
3 years ago
A scientist found a new bacteria in a hot water sulfur spring that uses sulfur as a source of energy instead sunlight. What kind
Sergio039 [100]
Chemosynthetic bacteria or chemoautotropic bacteria is the new bacteria that was found by scientists in a hot water sulfur spring that uses sulfur as a source of energy instead of sunlight. This kind of bacteria can survive at a higher temperature than most organisms can.The bacteria uses the toxic hydrogen sulfide to produce organic materials by the process of chemosynthesis. These bacteria are a source of life for several other organisms that flourish in such conditions. The bacteria grows and forms a thick mat and this attracts several other organisms as the bacteria becomes a source of food.
5 0
3 years ago
camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Usin
son4ous [18]

The question is incomplete. Here is the complete question.

The image below was taken with a camera that can shoot anywhere between one and two frames per second. A continuous series of photos was combined  for this image, so the cars you see are in fact the same car, but photographed at differene times.

Let's assume that the camera was able to deliver 1.3 frames per second for this photo, and that the car has a length of approximately 5.3 meters. Using this information and the photo itself, approximately how fast did the car drive?

Answer: v = 6.5 m/s

Explanation: The question asks for velocity of the car. Velocity is given by:

v=\frac{\Delta x}{\Delta t}

The camera took 7 pictures of the car and knowing its length is 5.3, the car's displacement was:

Δx = 7(5.3)

Δx = 37.1 m

The camera delivers 1.3 frames per second and it was taken 7 photos, so time the car drove was:

1.3 frames = 1 s

7 frames = Δt

Δt = 5.4 s

Then, the car was driving:

v=\frac{37.1}{5.4}

v = 6.87 m/s

The car drove at, approximately, a velocity of 6.87 m/s

7 0
3 years ago
What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach
Olin [163]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

I(\tau)=0.051 A

b

I(3 \tau)=0.076 A

c

I_c= 0.08 A

Explanation:

From the question we are told that

                I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R

From the question we are told to find I(\tau) when t=0  equals the time constant (\tau)

That is to obtain I(\tau).This  is mathematically represented as

                   I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })

             Substituting 12 V for \epsilon and 150Ω for R

                     I(\tau) = \frac{12}{150} (1- e^{-1})

                            =0.051 A

From the question we are told to find I(3 \tau) when t=0  equals the 3 times the  time constant (\tau)

That is to obtain I(3\tau).This  is mathematically represented as

                 I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })

                  I(\tau) = \frac{12}{150} (1- e^{-3})

                        =0.076 A

As tends to infinity \frac{\infty}{\tau}  = \infty

So I_c would be mathematically evaluated as

               I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})

                   = \frac{12}{150}

                   = 0.08 A

5 0
3 years ago
how long does it take a 750watt heater operating at full rating to rais the temperature of 1kg of water From 40°C to 70°C {S.H.C
siniylev [52]

Answer:

168 seconds (2 min 48 s)

Explanation:

Find the heat absorbed by the water.

q = mCΔT

q = (1 kg) (4200 J/kg/K) (70°C − 40°C)

q = 126,000 J

Power is energy per time.

P = q / t

750 W = 126,000 J / t

t = 168 s

It takes 168 seconds (2 min 48 s).

6 0
3 years ago
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