Answer:
<em>Increase in wave frequency only</em>
The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.
<u>Explanation:</u>
- For the above problem, we have the case as no<n1 and n2 < n1 .
- so we have(1<1.5;1.4<1.5)To find the wavelengths of the light that is not reflected in the air.
- Since the phase changes are not common on both the surfaces/
- we have the formula, λ=2d n²/m ( where m=1,2,3,4,5...)
- solving the problem we get,
- λ5= 600 nm, λ6= 500 nm, λ7=428 nm
- The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.
From the data given, the final velocity is equal to 6 m/s. This is from the equation a = vf - vo / t. The second kinetic equation to be used to determine the distance traveled is 2ax = vf2 - vo2. Substituting, 2*0.6*x = 6^2 - 3^2 ; x then is equal to 22.5 meters
Answer:
(D) It is stronger when the objects are closer.
Explanation:
Newton's universal law 9f gravitation