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andrew11 [14]
3 years ago
7

On a frozen pond, a 8.54-kg sled is given a kick that imparts to it an initial speed of ð£0=1.87 m/s. The coefficient of kinetic

friction between sled and ice is ðð=0.087. Use work and energy concepts to find the distance the sled moves before coming to rest.
Physics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:2.05 m

Explanation:

Given

Mass of sled m=8.54 kg

initial speed u=0.187 m/s

coefficient of kinetic Friction \mu _k=0.087

According to work-energy theorem work done by all the forces is change in Kinetic energy

W_{friction}=\frac{1}{2}mv_i^2-\frac{1}{2}mv_f^2

\mu _kmg\times d=\frac{1}{2}\times 8.54\times 1.87^2 ,where d= distance moved

0.087\times 8.54\times 9.8\times d=14.93

d=\frac{14.93}{7.281}

d=2.05 m

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A transformer has a primary coil with 106 turns and a secondary coil of 340 turns. The AC voltage across the primary coil has a
UkoKoshka [18]

To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.

From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

\frac{V_s}{V_p} = \frac{N_s}{N_p}

Where

V_p =  input voltage on the primary coil.

V_s=input voltage on the secondary coil.

N_p=  number of turns of wire on the primary coil.

N_s = number of turns of wire on the secondary  coil.

Replacing our values we have:

V_p = 128V

N_p = 106

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Replacing,

\frac{V_s}{128} = \frac{340}{106}

V_s = 410.56V

From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

V_s I_s = V_p I_p

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Therefore:

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I_s = \frac{(128)(6)}{410.56}

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121440 feet is 23 miles.

5280 x 23= 121440

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