Carbon monoxide prevents

What is the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosp

sineoko [7]

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

<h3>How to find the weight of a column of air?</h3>

As we know that the expression of pressure as,

$P=\frac{F}{A}$

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

$P=1atm=1.013*10^5Pascals$

From this, the value of weight will be,

$F=mg=P*A=1.013*10^5*4.5=4.56*10^5N$

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

Learn more about the pressure here:

brainly.com/question/12830237

#SPJ4

4 0

2 years ago

Learning Goal: How do 2 ordinary waves build up a "standing" wave? A very generic formula for a traveling wave is: y1(x,t)=Asin(

zheka24 [161]

Answer:

Explanation:

=Asin(kx−ωt). This general mathematical form can represent the displacement of a string, or the strength of an electric field, or the height of the surface of water, or a large number of other physical waves!

Part C Find ye(x) and yt(t). Remember that yt(t) must be a trig function of unit amplitude. Express your answers in terms of A, k, x, ω, and t. Separate the two functions with a comma. Use parentheses around the argument of any trig functions.

Part E At the position x=0, what is the displacement of the string (assuming that the standing wave ys(x,t) is present)? Part G From

Part F we know that the string is perfectly straight at time t=π2ω. Which of the following statements does the string's being straight imply about the energy stored in the strJHJMNMMUJJHTGGHing?

a.There is no energy stored in the string: The string will remain straight for all subsequent times.

b.Energy will flow into the string, causing the standing wave to form at a later time.

c.Although the string is straight at time t=π2ω, parts of the string have nonzero velocity. Therefore, there is energy stored in the string.

d.The total mechanical energy in the string oscillates but is constant if averaged over a complete cycle.

3 0

3 years ago

5. Suppose a skydiver (mass = 75kg) is falling toward the Earth. When the skydiver is 100m above the Earth he is moving at 60m/s

Anna71 [15]

1) Gravitational potential energy: 73 500 J

2) Kinetic energy: 135 000 J

3) Mechanical energy: 208 500 J

Explanation:

1)

The gravitational potential energy of an object is the energy possessed by the object due to its position in the Earth's gravitational field, and it is given by

$U=mgh$