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irinina [24]
3 years ago
8

What is the acceleration an object experiences on earth?w?

Physics
1 answer:
mariarad [96]3 years ago
3 0
9.8 m/s^s and thats the earths gravitational force!
Hope it helps
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The voltage across the terminals of a generator is 5.7 v when it supplies a current of 0.3 A. It becomes 5.1 V when I=0.9A. Find
snow_tiger [21]

Answer:

  • The emf of the generator is 6V
  • The internal resistance of the generator is 1 Ω

Explanation:

Given;

terminal voltage, V = 5.7 V, when the current, I = 0.3 A

terminal voltage, V = 5.1 V, when the current, I = 0.9 A

The emf of the generator is calculated as;

E = V + Ir

where;

E is the emf of the generator

r is the internal resistance

First case:

E = 5.7   + 0.3r -------- (1)

Second case:

E = 5.1 + 0.9r -------- (2)

Since the emf E, is constant in both equations, we will have the following;

5.1 + 0.9r = 5.7   + 0.3r  

collect similar terms together;

0.9r - 0.3r = 5.7 - 5.1

0.6r = 0.6

r = 0.6/0.6

r = 1 Ω

Now, determine the emf of the generator;

E = V + Ir

E = 5.1 + 0.9x1

E = 5.1 + 0.9

E = 6 V

6 0
3 years ago
Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc
Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2

The data given are;

  • m1 = 281kg
  • u1 = 2.82m/s
  • m2 = 209kg
  • u2 = -1.72m/s
  • v1 = ?

Let's substitute the values into the equation.

v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

brainly.com/question/7694106

4 0
2 years ago
For a particular scientific experiment, it is important to be completely isolated from any magnetic field, including the earth's
Alexus [3.1K]

Answer:

50000 μT

Explanation:

From the given information:

the diameter of the loop = 1.0 mm = 0.001 m

no of turns (N) = 200

current (I) = 0.199 A

radius = d/2 = 0.001/2

= 5 × 10⁻⁴ m

Recall that;

the magnetic field at the centre of circular wire is:

= \dfrac{\mu I N}{2R}

= \dfrac{4 \pi \times 10^{-7} \times 200 \times0.199}{2\times 5\times 10^{-4}}

= 0.05 T

= 50000 μT

Since the centre of the earth's magnetic field is given to be equal to the magnetic field produced by the wire, then:

the earth's magnetic field = 50000 μT

5 0
3 years ago
How to measure the density of a white dwarf if its diameter is 1000 km and weighs 10³⁰ kg?
Afina-wow [57]

Well, first of all, 10³⁰ kg is its mass, not its weight.

-- Density of anything is (its mass) divided by (its volume).

-- You know the white dwarf's mass.

-- The volume of any sphere is  (4/3) (pi) (radius)³

-- The radius is  1/2  of the diameter.

--  Now you have the ball.  Run with it.

I did it quickly and got  (1.91 x 10¹²) kilogram/meter³ .
That may be wrong.  You have to check it.  And even
if it's correct, you probably want to express density in
units of gram/cm³ the way everybody always does.

6 0
3 years ago
Which tools would Sara use to find and irregularly shaped objects mass in volume?
pogonyaev
To find the mass and volume of irregularly shaped object. One can use the balance to find the weight, and to find the volume of the object water should be poured in the beaker and note the level of water.
8 0
3 years ago
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