Answer:
copper(I) bromide: CuBr
copper(I) oxide: Cu₂O
copper(II) bromide: CuBr₂
copper(II) oxide: CuO
iron(III) bromide: FeBr₃
iron(III) oxide: Fe₂O₃
lead(IV) bromide: PbBr₄
lead(IV) oxide: PbO₂
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Answer:
ans. is 0.05
Explanation:
molarity=(mole of solute)/(litre of solution)
I think the correct answer from the choices listed above is option C. The mass of an ice cube is the total amount of water in the ice cube. Ice is the solid form of water. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Explanation:
Metals react with oxygen to form basic oxides while they react with water to form alkaline solutions. Also, acidic oxides are oxides of nonmetals and they react with water to form acidic solutions.
Trends on the period table shows the variation of metallic character as you move across and down the periodic table. Metallic character of a element decreases across the period on the periodic table from left to right because atoms readily accept electrons in their outermost shell to form stable configurations. Metallic character increases as you move down the group in the periodic table and this is because electrons become easier to lose as the atomic radius increases (more outer shells are added), where there is decreasing attraction between the nucleus and the valence electrons.
So down the group, the acidity of oxide reaction with water decreases because the oxides are more basic down the group while across the period, the acidity of oxide increases because acidic oxides are formed as we move across the period.
When an electron passes through the magnetic field of a horseshoe magnet, the electron's direction is changed.
Path of an electron in a magnetic field
The force (F) on wire of length L carrying a current I in a magnetic field of strength B is given by the equation:
F = BIL
But Q = It and since Q = e for an electron and v = L/t you can show that :
Magnetic force on an electron = BIL = B[e/t][vt] = Bev where v is the electron velocity
In a magnetic field the force is always at right angles to the motion of the electron (Fleming's left hand rule) and so the resulting path of the electron is circular.
Therefore :
Magnetic force = Bev = mv2/r = centripetal force
v = [Ber]/m
and so you can see from these equations that as the electron slows down the radius of its orbit decreases.
If the electron enters the field at an angle to the field direction the resulting path of the electron (or indeed any charged particle) will be helical. Such motion occurs above the poles of the Earth where charges particles from the Sun spiral through the Earth's field to produce the aurorae.
To learn more about electron : brainly.com/question/860094
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