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Yuliya22 [10]
3 years ago
7

In the Millikan oil droplet experiment, the oil is sprayed from an atomizer into a chamber.The droplets are allowed to pass thro

ugh the hole into the chamber so that their fall can be observed. The top and bottom of the chamber consist of electrically charged plates. The upper plate is positively charged, and the lower plate is negatively charged. X rays are introduced into the chamber so that when they strike the oil droplets, the droplets will acquire one or more negative charges. The electric field (voltage) is applied to the metal plates.Which of the following applies? Can have more than one answer.a. In the presence of an electric field, the negatively charged oil droplet moves freely toward the negatively charged plate.b. In the absence of an electric field, the oil droplet falls freely due to the gravitational force.c. If Fe is greater than Fg , the negatively charged oil droplet will move freely toward the negatively charged plate.d. If Fe is increased until it is equal to Fg , the negatively charged oil droplet will remain stationary.
Chemistry
2 answers:
Marina CMI [18]3 years ago
4 0

Answer:idk XD

Explanation:

Dmitry [639]3 years ago
4 0

Answer:

is this just a passage?

Explanation:

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Recall all the models you described in task 1. Think about the results each model would predict for Thomson’s experiment. Which
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Answer:

J.J. Thomson’s experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged “soup.”

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2 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
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Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

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it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
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so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base

(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.

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