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Stells [14]
3 years ago
8

Given the balanced equation, calculate the mass of product that can be prepared from 2.10 g of zinc metal. 2Zn(s)+O2(g)→2ZnO(s)

Express your answer with the appropriate units.
Chemistry
1 answer:
vazorg [7]3 years ago
7 0

Botox & Glade Juice w/ Apple Cider Vinegar

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Blank is most if the compounds that make up living things?
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carbon

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Carbon forms compounds that make up about 18 percent of all the matter in living things. The processes by which organisms consume carbon and return it to their surroundings constitute the carbon cycle.

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2 years ago
6. Explain a situation in which elastic potential energy could be transformed into kinetic energy.
dsp73

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When you pull a rubber band there is elastic potential energy stored in the rubber band but once you let go of either side the EPE turns into Kinetic Energy.

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In which compound do the atoms have the greatest difference in electrongativity?
weqwewe [10]

Explanation:

cesium fluoride is one of the compound

5 0
3 years ago
What is the percent of H in NH3
ale4655 [162]

\frac{h3}{nh3}

\frac{1.008 \times 3}{(14.01) + (1.008 \times 3)}  \times 100\% =
ok, now press calculator. i dont have it now.
6 0
3 years ago
Read 2 more answers
What mass of aluminum is needed to produce 0.500 mole of aluminum chloride?
3241004551 [841]

Answer:  " 13.5 g Al " ;

                    →  that is:  "13.5 grams of aluminum."

<u>____________________________</u>

Explanation:

<u>____________________________</u>

<u>Note</u>: What is missing from the question is the "balanced chemical equation" for the "chemical reaction" that contains:

 The reactants:  "aluminum (Al) " ;  and "chlorine (Cl) " ;  and:

 The product:    "aluminum choloride (AlCl₃) " .

____________________________

The "balanced chemical equation" is:

____________________________

        2 Al   +   3 Cl₂   →   2 AlCl₃   ;

_____________________________

<u>Note</u>: The molecular weight of "aluminum (Al)" is:   " 26.98 g /mol " .

____________________________

So:  We call solve using a technique known as:  "dimensional analysis" :

____________________________

  0.500 mol AlCl₃ * (\frac{2mol Al}{2mol AlCl_{3} }) * (\frac{26.98g Al}{1 mol Al}) = ?

____________________________

<u>Note</u>:  The units of "mol AlCl₃" cancel out to "1' ; and:

          The  units of "mol Al" cancel out to "1" ; and we are left with:

____________________________

 " \frac{(0.500 * 2 * 26.98)}{2}   g Al ["grams of aluminum"] ;

____________________________

<u>Note</u>: We can "cancel out the "2's" ; since "2/2 = 1 " ; and we have:

 →  (0.500 * 26.98) g Al ;

    = 13.49 g Al ;

         →  Round to 3 (Three) significant figures;

         →  Since:  "0.500" has 3 (Three) significant figures:

____________________________

   =  13.5 g Al ; that is:  "13.5 grams of aluminum."

____________________________

 Hope this is helpful!  

      Best wishes to you in your academic pursuits—and within the "Brainly" community!

____________________________

3 0
3 years ago
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