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Stells [14]
3 years ago
8

Given the balanced equation, calculate the mass of product that can be prepared from 2.10 g of zinc metal. 2Zn(s)+O2(g)→2ZnO(s)

Express your answer with the appropriate units.
Chemistry
1 answer:
vazorg [7]3 years ago
7 0

Botox & Glade Juice w/ Apple Cider Vinegar

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What is an echo? (1 point)
zaharov [31]

Answer:

The reflection of sound waves

Explanation:

An echo is a reflection of sound that bounces of of one thing to another.

4 0
3 years ago
Read 2 more answers
A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

4 0
3 years ago
What is the number after an element in a chemical equation called? Example: H2
Sophie [7]

Answer:

the answer to your problem is A.Subscript...BRAINLIEST

6 0
3 years ago
A sample of fluorine contains isotopes with different masses; F-19 and F-18. In the sample 94% of the
zalisa [80]

The relative mass of the sample : 18.94

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.%

F-19 = 94% of the sample

F-18 = 100%-94%=6% of the sample

The relative mass :

\tt = 0.94\times 19+0.06\times 18\\\\=18.94

7 0
3 years ago
Which process occurs when uranium-235 is bombarded with neutrons to produce smaller nuclei?
11111nata11111 [884]
The correct answer is B: fission
5 0
3 years ago
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