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LuckyWell [14K]
4 years ago
16

The function h(t) = –16t2 + 96t + 6 represents an object projected into the air from a cannon. The maximum height reached by the

object is 150 feet. After how many seconds does the object reach its maximum height? 2 seconds 3 seconds 6 seconds 9 seconds
Physics
2 answers:
Rainbow [258]4 years ago
6 0

Answer:

3 seconds

Explanation:

Since h(t) represents the height and t represents the time, we can set the equation equal to 150 to find t.

-16t^2+96t+6=150

Subtract 150 from both sides to set the equation equal to 0, to find the solutions.

-16t^2+96t-144=0

Factor out -16, because all of the terms are divisible by it.

-16(t^2+6t+9)=0

Now we can focus on the terms inside the parenthesis and factor it again.

t^2-6t+9=0

We need to find two value that can be multiplied to get 9 and added to get -6.

-3 and -3 works.

Thus, we get (x-3)(x-3).

Now solve for 0.

x-3=0

x=3

The object reaches its maximum height after 3 seconds.

svp [43]4 years ago
6 0

Answer:

3 seconds

Explanation:

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3 years ago
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3 years ago
How many volts would it take to push 1 amp through a resistance of 1 ohm?
ELEN [110]
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5 0
3 years ago
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The neurons of giant squids, for example, consist of axons with very large radii, which allows the squid to react very quickly w
Alinara [238K]

Answer:

100

Explanation:

\rho_m = Resistivity of axon

r = Radius of axon

t = Thickness of the membrane

\rho_a = Resistivity of the axoplasm

Speed of pulse is given by

v=\sqrt{\dfrac{\rho_mrt}{2\rho_a}}

So, radius is given by

r=\dfrac{2\rho_a}{\rho_mt}v^2

If radius is increased by a factor of 10 new radius will be

r_2=\dfrac{2\rho_a}{\rho_mt}(10v)^2\\\Rightarrow r_2=100\dfrac{2\rho_a}{\rho_mt}v^2\\\Rightarrow r_2=100r

So, The radius will increase by a factor of 100.

5 0
4 years ago
What is the force of gravity (from the Earth) on the 700kg satellite if it’s 10km above the Earth's surface?
BabaBlast [244]

Answer:

g = 4.7 × 10^{-16} m/s^{2}

Explanation:

Given that the mass of the satellite = 700 kg, and 10,000 m above the earth;s surface.

From Newton's second law,

 F = mg ............... 1

From Newton's gravitation law,

F = \frac{GMm}{r^{2} } .................. 2

Where: F is the force, G is the gravitational constant, M is the mass of the first body, m is the mass of the second body, g is the gravitational force and r is the distance between the centers of the two bodies.

Equate 1 and 2 to have,

mg = \frac{GMm}{r^{2} }

⇒   g = \frac{GM}{r^{2} }

But; G =  6.67 × 10^{-11} N m^{2} Kg^{-2}, M = 700 Kg, r = 10000 m

Thus,

g = \frac{6.67*10^{-11*700} }{10000^{2} }

  = \frac{4.669*10^{-8} }{1*10^{8} }

  = 4.669 × 10^{-16} m/s^{2}

The force of gravity on the satellite is 4.7 × 10^{-16} m/s^{2}.

5 0
4 years ago
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