Manuel is holding a 5 kg box. How much force us the box exerting on him? in what direction
1 answer:
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Complete question:
Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?
Part B: What is the momentum of a proton traveling at 0.62 c ?
Answer
a)Who would have aged less=The Captain would have aged less
b)
Explanation:
From the question we are told that
Length measured by captain
Speed of rocket past tje space dock
Length measured by space-dock personnel
a)
Generally time moves slower when moving at speed of light, due to time dilation or variation.
Who would have aged less=The Captain would have aged less
b)
Generally the equation for Relativistic Momentum is mathematically given as
Answer:
Winner wins by 0.969 s
Explanation:
For the Porche:
Given:
Displacement of Porsche s = 400 m
Acceleration of Porsche a = 3.4 m/s^2
From Newton's second equation of motion,
(u = 0 as the car was initially at rest)
Substituting the values into the equation, we have
= 235.29 / 3.4
t = 15.33 s
For the Honda:
Displacement of Honda = 310 m
Acceleration of Honda = 3 m/s^2
Applying Newton's second equation of motion
(u = 0 for same reason)
Substituting the values into the equation, we obtain
= 620 / 3
t = 14.37 s
Hence
The winner (honda) wins by a time interval of = 15.33 - 14.37
=0.969 s
Answer:
W = 0 J
Explanation:
The amount of work done by gas at constant pressure is given by the following formula:
where,
W = Work done by the gas
P = Pressure of the gas
ΔV = Change in the volume of the gas
Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:
<u>W = 0 J</u>