Question

When sodium is excited in a flame, two ultraviolet spectral lines at (wave length symbol)=372.1 nm and (wave length symbol)=376.4 nm respectively are emitted. Which wavelength represents photons with

Answer 1

Answer:

- 372.1 nm -> Higher energy.

- 376.4 nm -> Lower energy.

Explanation:

Hello,

By considering that for a photon the shorter the wavelength the higher the energy, since the two wavelengths are very close, one could distinguish them as follows:

- 372.1 nm -> Higher energy.

- 376.4 nm -> Lower energy.

Furthermore, at lower wavelengths, we find higher frequencies.

- 372.1 nm -> Higher frequency.

- 376.4 nm -> Lower frequency.

Best regards.

Answer 2

Higher energy = shorter wavelength
Frequency is one cycle over an amount of time (seconds)
So higher frequency = higher energy = shorter wavelength