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Vedmedyk [2.9K]
3 years ago
12

When sodium is excited in a flame, two ultraviolet spectral lines at (wave length symbol)=372.1 nm and (wave length symbol)=376.

4 nm respectively are emitted. Which wavelength represents photons with
Chemistry
2 answers:
elena55 [62]3 years ago
8 0

Answer:

- 372.1 nm -> Higher energy.

- 376.4 nm -> Lower energy.

Explanation:

Hello,

By considering that for a photon the shorter the wavelength the higher the energy, since the two wavelengths are very close, one could distinguish them as follows:

- 372.1 nm -> Higher energy.

- 376.4 nm -> Lower energy.

Furthermore, at lower wavelengths, we find higher frequencies.

- 372.1 nm -> Higher frequency.

- 376.4 nm -> Lower frequency.

Best regards.

uranmaximum [27]3 years ago
5 0
<span>Higher energy = shorter wavelength
Frequency is one cycle over an amount of time (seconds)
So higher frequency = higher energy = shorter wavelength</span>
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Answer:

Phosphorus is more electronegative than hydrogen

Explanation:

Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons towards itself thereby making a molecule to be polar. The Pauling scale is the most commonly used to measure electronegativity. Fluorine (the most electronegative element) is assigned a value of 4.0 on the Pauling's scale, and values range down to caesium and francium which are the least electronegative elements.

Electronegativity increases from left to right across the periodic table (across the period) hence, phosphorus is far more electronegative than hydrogen. Being more electronegative than hydrogen, phosphorus attracts the bonding electron pair of the P-H bond closer to itself than hydrogen. Since the electrons of the bond are closer to phosphorus than hydrogen, the phosphorus atom acquires a partial negative charge while the hydrogen atom acquires a partial positive charge.

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3 years ago
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Explanation:

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Then plug that answer into the Power formula.

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sp2606 [1]

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The answer to your question is: c

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