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Vedmedyk [2.9K]
3 years ago
12

When sodium is excited in a flame, two ultraviolet spectral lines at (wave length symbol)=372.1 nm and (wave length symbol)=376.

4 nm respectively are emitted. Which wavelength represents photons with
Chemistry
2 answers:
elena55 [62]3 years ago
8 0

Answer:

- 372.1 nm -> Higher energy.

- 376.4 nm -> Lower energy.

Explanation:

Hello,

By considering that for a photon the shorter the wavelength the higher the energy, since the two wavelengths are very close, one could distinguish them as follows:

- 372.1 nm -> Higher energy.

- 376.4 nm -> Lower energy.

Furthermore, at lower wavelengths, we find higher frequencies.

- 372.1 nm -> Higher frequency.

- 376.4 nm -> Lower frequency.

Best regards.

uranmaximum [27]3 years ago
5 0
<span>Higher energy = shorter wavelength
Frequency is one cycle over an amount of time (seconds)
So higher frequency = higher energy = shorter wavelength</span>
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Answer:

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Explanation:

Hello,

This case in which the Hess method is applied to compute the required chemical reaction. Thus, we should arrange the given first two reactions as:

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Best regards.

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