Answer:
(2) Half of the active sites are occupied by substrate.
Explanation:
The Michaelis–Menten equation is the rate equation for a one-substrate enzyme-catalyzed reaction. It is an expression of the relationship between the initial velocity V₀ of an enzymatic reaction, the maximum velocity Vmax, and substrate concentration [S] which are all related through the Michaelis constant, Km.
Mathematically, the Michaelis–Menten equation is given as:
V₀ = Vmax[S]/Km + [S]
A special relationship exists between the Michaelis constant and substrate concentration when the enzyme is operating at half its maximum velocity, i.e. at V₀ = Vmax/2
substituting, Vmax/2 = V₀ in the Michaelis–Menten equation
Vmax/2 = Vmax[S]/Km + [S]
dividing through with Vmax
1/2 = [S]/Km + [S]
2[S] = Km + [S]
2[S] - [S] = Km
[S] = Km
Therefore, when the enzyme is operating at half its maximum velocity, i.e. when half of the active sites are occupied by substrate, [S] = Km
Arteries carry blood away from the heart and veins carry blood back to the heart. Hope that helps (:
Here are the given:
<span>ΔHf° = –423 kJ/mol
</span> ΔHsub = 119 kJ/mol
IE = 469 kJ/mol
ΔHEA = –301 kJ/mol
BE = 161 kJ/mol
The lattice energy of the compound is solved using the formula:
U = <span>ΔHf° - </span>ΔHsub - BE - IE - ΔHEA
U = -423 - 119 - 161 - 469 - (-301)
U = -871 kJ/mol
Therefore, the lattice energy is 871 kJ/mol (released).
Farmers use the property of density of cranberries to harvest the crop because an object with a density less than, in this case, water, it will float.
When farmers flood cranberry bogs with water, they know that cranberries have a density less than about 1 g/mL. Because of this, cranberries will float to the top of water and can be easily harvested.
<span>When naming compounds, the first thing you need to do is decide if the compound is ionic or molecular. *Ionic compounds
will contain both metals and non-metals, or at least one polyatomic
ion. *Acids will always include the (aq) symbol beside the formula, and
the name will include the word acid.</span>