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4vir4ik [10]
2 years ago
13

A binary compound created by reaction of chromium and an unknown element E contains 68.47% Cr and 31.53% E by mass. If the formu

la of the compound is Cr2E3, calculate the atomic mass of E.

Chemistry
2 answers:
chubhunter [2.5K]2 years ago
8 0

Answer:

The molar mass of E = 15.96 g/mol

Explanation:

Step 1: Data given

The compound Cr2E3 contains 68.47 % Cr and 31.53 % E

The molar mass of Cr = 52 g/mol

⇒ 2*52 = 104 g/mol

The molar mass of Cr2E3 = 2*52 g/mol + 3X

Step 2: Calculate mass of Cr2E3

Cr is 68.47 %

Mass of Cr = 104 grams

Cr2E3 is 100%

Mass of Cr2E3 = 151.89 grams

Molar mass of Cr2E3 = 151.89 g/mol

Step 3: Calculate mass of E

Mass of E3 = mass of Cr2E3 - mass of Cr

Mass of E3 = 151.89 grams - 104 grams

Mass of E3= 47.89 grams

Mass of E = 15.96 grams

The molar mass of E = 15.96 g/mol

Mrac [35]2 years ago
4 0

Answer: The atomic mass of E is 16

Explanation:Please see attachment for explanation

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Complete the following radioactive decay problem.<br>222 86 RN to 4 2 HE + ?​
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Answer:

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Explanation:

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g When aqueous solutions of and are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M is mixed
solong [7]

The question is incomplete, the complete question is:

When aqueous solutions of NaCl and Pb(NO_3)_2 are mixed, a solid forms. Determine the mass of solid formed when 140.7 mL of 0.1000 M NaCl is mixed with an excess of an aqueous solution of

<u>Answer:</u> The mass of lead chloride produced is 1.96 g

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{ \text{Volume of solution (mL)}} .....(1)

Given values:

Molarity of NaCl = 0.1000 M

Volume of the solution = 140.7 mL

Putting values in equation 1, we get:

0.1000=\frac{\text{Moles of NaCl}\times 1000}{140.7}\\\\\text{Moles of NaCl}=\frac{0.1000\times 140.7}{1000}=0.01407mol

The chemical equation for the reaction of NaCl and lead nitrate follows:

Pb(NO_3)_2(aq)+2NaCl(aq)\rightarrow PbCl_2(s)+2NaNO_3(aq)

By the stoichiometry of the reaction:

If 2 moles of NaCl produces 1 mole of lead chloride

So, 0.01407 moles of NaCl will produce = \frac{1}{2}\times 0.01407=0.007035mol of lead chloride

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(2)

Molar mass of lead chloride = 278.1 g/mol

Plugging values in equation 2:

\text{Mass of lead chloride}=(0.007035mol\times 278.1g/mol)=1.96g

Hence, the mass of lead chloride produced is 1.96 g

8 0
3 years ago
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