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vladimir1956 [14]
3 years ago
14

Why is it so difficult to experience the northern lights here in michigan? I need to know noww

Chemistry
1 answer:
Anni [7]3 years ago
7 0

Answer:

Think about where you're located on the globe. That'll tell you your answer

Explanation:

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The oxygen atom in a water molecule A is electrically neutral. B carries a negative electrical charge. C carries a positive elec
Klio2033 [76]

Answer: The oxygen atom in a water molecule carries a negative electrical charge.

Explanation:

A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.

Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom (attached with an electronegative atom e.g. O, N and F) and an electronegative atom (O,N and F).

In , H_2O , O is a highly electronegative atom attached to a H atom through a covalent bond. Therefore O atom gets partial negative charge and H atoms get partial positive charge.  

7 0
3 years ago
What is the importance of a special habitat?
vfiekz [6]
They meet all the environmental conditions an organism needs to survive
8 0
2 years ago
A sample of nitrogen gas, (N2), occupies 45.0 mL at 27.00∘C and 80.0 kPa. What will be the pressure if the gas is cooled to −73.
maxonik [38]

Answer:

The new pressure is 53.3 kPa

Explanation:

This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.

T° increase → Pressure increase

T° decrease → Pressure decrease

In this case, temperature was really decreased. So the pressure must be lower.

P₁ / T₁ = P₂ / T₂

80 kPa / 300K =  P₂/200K

(80 kPa / 300K) . 200 K = P₂ →  53.3 kPa

6 0
3 years ago
Colo Kelskemdkdood is the time of the time I
Valentin [98]

Answer:

Explanation:

what?

8 0
3 years ago
Predict the boiling point of water at a pressure of 1.5 atm.
Lina20 [59]

Answer:

100.8 °C

Explanation:

The Clausius-clapeyron equation is:

ln\frac{P_{1} }{P_{2}} =-Δ\frac{H_{vap}}{r} (\frac{1}{T_{2}}-\frac{1}{T_{1}}  )

Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'

Isolating for T2 gives:

T_{2}=(\frac{1}{T_{1}} -\frac{Rln\frac{P_{2}}{P_{1}} }{Delta H_{vap}}

(sorry for 'deltaHvap' I can not input symbols into equations)

thus T2=100.8 °C

7 0
3 years ago
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