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2 years ago

When electrons are lost, a ( )

1 answer:

3 0

When electrons are lost a positive ion is formed. When electrons are gained, a negative ion is formed. I hope this helps

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What assumption can be made about the densities of two different spheres that have

Triss [41]

Answer:

Their densities are different as well

Explanation:

Density is worked out by dividing mass by volume. If the mass was the same then the densities would be as well. But it's not.

How many marks is this question?

8 0

3 years ago

A 0.335 kg mass is attached to a spring and executes simple harmonic motion with a period of 0.38 s. The total energy of the sys

kramer

Answer:

$k=91.54 \frac{N}{m}$

Explanation:

The angular speed is defined as the angle traveled in one revolution over the time taken to travel it, that is, the period. Therefore, it is given by:

$\omega=\frac{2\pi}{T}\\\omega=\frac{2\pi}{0.38s}\\\omega=16.53\frac{rad}{s}$

The angular frequency of the simple harmonic motion of the mass-spring system is defined as follows:

$\omega=\sqrt{\frac{k}{m}}$

Here, k is the spring's constant and m is the mass of the body attached to the spring. Solving for k:

$\omega^2=\frac{k}{m}\\k=m\omega^2\\k=0.335kg(16.53\frac{rad}{s})^2\\k=91.54 \frac{N}{m}$

6 0

3 years ago

Why doesn't the moon hit Earth's<br> surface?

kicyunya [14]

Because the Moon is never still. It constantly moves around us. Without the force of gravity from the Earth, it would just float away into space.

7 0

3 years ago

Read 2 more answers

A 12000 kg railroad car is traveling at a 2 m/s when it strikes another 10000 kg railroad is at rest. If the car lock together w

zimovet [89]

The final speed is $1.09m\frac{m}{s}$

Why?

To calculate the final speed, we need to know that we are working with an inelastic collision, it means that both bodies stick together after the colission. We can calculate the final speed of the bodies (if exists) using the following equation:

$m_{1}v{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{f}$

We are given the following information:

$m_{1}=12000kg\\v_{1}=2\frac{m}{s}\\m_{2}=10000kg\\v_{2}=0\frac{m}{s}(at rest)$

So, substituting and calculating, we have:

$m_{1}v{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{f}\\\\12000kg*2\frac{m}{s}+10000kg*0\frac{m}{s}=(12000kg+10000kg)*v_{f}\\\\v_{f}=\frac{24000\frac{kg.m}{s} }{22000kg}=1.09m\frac{m}{s}$

Hence, the final speed is 1.09 m/s.

Have a nice day!

5 0

3 years ago

Which unit would be most suitable for its scale?

Cloud [144]

Answer:

Mm, thats the answer trust me men

5 0

3 years ago