Length of the pipe = 0.39 m
Third harmonic frequency = 1400 Hz
For the third harmonic:
Wavelength =
The center of the open pipe will host a node and the nearest anti - node from the center will be at the 0.25 × wavelength
Distance from center = 0.25 × wavelength
Distance =
Plugging the value of the length of the pipe (L) = 0.39 m = 39 cm
Distance =
Distance from the center to the nearest anti - node = 6.5 cm
Hence, the nearest distance to the anti - node from the center = 6.5 cm
So, option C is correct.
Answer:
the charge the photoelectric effect induce is 0.132 × 10⁻¹¹ C
Explanation:
energy of ultraviolet light =
=
=7.91 × 10⁻¹⁹ J
=4.94 e V
energy released by the electron = 4.94 - 4.70
= 0.24 e V
potential at the surface of sphere =
0.24 =
Q = 0.132 × 10⁻¹¹ C
hence, the charge the photoelectric effect induce is 0.132 × 10⁻¹¹ C
Answer:
answer in the picture provided.
Explanation:
Answer:
Initial velocity of the jaguar: 49 (answer d)
Explanation:
Considering that this uniformly accelerated problem (with negative acceleration since the jaguar was reducing its velocity to full stop), does not include the time the jaguar was skidding , we can use the kinematic equation that doesn't include time, but relates velocities (initial and final) with the acceleration (), and the distance "D" covered during the accelerated motion:
For our problem, the initial velocity ( is our unknown, the final velocity is zero (
- since the jaguar stops in the process), the negative acceleration is given as
, and the distance D of the skid marks is said to be 300 m in length. Therefore:
Which we can round to 49