(a) What is
the potential energy: PE = -G * M * m/r
Where: M is the mass of the earth which is 5.98 * 10^24 kg.
m is the mass of the satellite.
r is the space from the center of the earth to the satellite
To conclude this distance add the radius of the earth to the
altitude. Radius of the earth is 6.38 * 10^6 meters.
r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6
PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 =
4.71240095 * 10^9 J
(b) magnitude of the gravitational force exerted by the
Earth
Fg = G * M * m/r^2
Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 =
562.3078873 N
(c) There are no other forces that the satellite exert on
the Earth. So therefore, it is 0.
a because of the following rate I do not now I saw it on the other one
Answer:
a,= 1m/second. b,= 0m/ second ( constance,no movement)
Answer:
Current in the capacitor increases as the frequency of the generator increases
Explanation:
Xc = 1/2πfC = 1/ wC
Since frequency is inversely proportional to reactance of a capacitor,
as the frequency increases, the capacitance decreases and tend towards behaving like a wire with zero resistance as such the generator send high current to the capacitor, the current in the capacitor increases.
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Susan D.
i dont know if that’s what you’re looking for but here ya go.
