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horrorfan [7]
3 years ago
7

Elizabeth, with a mass of 56.1kg stands on a scale in an elevator. Total mass of elevator plus Elizabeth=850kg. As the elevator

starts moving, the scale reads 450N. Find the acceleration and tension in the cable.
Physics
1 answer:
Reil [10]3 years ago
7 0

Answer:

acceleration = 1.79 m/s^2

Tension = 6817 N

Explanation:

First let's find Elizabeth's weight:

P = m*g = 56.1 * 9.81 =  550.34\ N

Her weight is greater than the normal force (N = 450 N), so the elevator is going downwards.

The acceleration of Elizabeth is given by:

P - N = m*a

Where P is the weight of Elisabeth, N is her normal force, m is her mass and a is the acceleration. Then, we have that:

56.1*9.81 - 450 = 56.1*a

a = 100.34 / 56.1 = 1.79\ m/s^2

The tension in the cable is given by:

P - T = m*a

In this case, we use the total mass, so we have:

850*9.81 - T = 850*1.79

T = 850 * 8.02 = 6817\ N

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From the question, The kinetic energy of the fired arrow is equal to the work done by the bale of hale in stopping the arrow.

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From the question,

Given:

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Learn more about average stooping force here: brainly.com/question/13370981

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2 years ago
A friction force of 280 N exists between a cart and the path. If the force of reaction is 766 N, what is the minimum action forc
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force of friction on the cart is given as

F_f = 280 N

here we also know the reaction force due to surface

R = 766 N

so we can say reaction force is given as

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766 = \sqrt{F_n^2 + 280^2}

F_n^2 = 766^2 - 280^2

F_n = 713 N

now by force balance we will say

F_y + F_n = mg

F_y = mg - F_n

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also we know that

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280 = \mu * 713

\mu = 0.39

now minimum force required to set this into motion

F_{min} = \frac{\mu mg}{\sqrt{1 + \mu^2}}

here we know that

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F_{min} = \frac{0.39* 713}{\sqrt{1 + 0.39^2}}

F_{min} = 259 N

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