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valkas [14]
2 years ago
5

A fighter plane is descending at 30 m/s. The pilot ejects, and the ejector seat accelerates him upwards at 120 m/s2 for 2 second

s. What is his velocity at the end of the 2 seconds?
Physics
1 answer:
katrin [286]2 years ago
4 0

Answer:

210m/s upwards

Explanation:

u= -30m /s

a= 120m/s^2

t=2s

v=u+at

=(-30)+(120x2)

=240-30

=210m/s

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Unknown:

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The centripetal acceleration is directed inward to keep the body from falling off the surface of the earth.

     centripetal acceleration  = \frac{v^{2} }{r}

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   also;

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  where w is the angular velocity

substituting in the equation for centripetal acceleration gives;

                 

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 also w = \frac{2 x pi}{T}

      therefore;

                 a = \frac{4 \pi  ^{2} r }{T^{2} }

 a = \frac{ 4 x 3.142^{2}  x 6.38 x 10^{16} }{86400^{2} }

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learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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