Magnitude of the force = 50N
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<u>Explanation:</u>
Let one force be X
And the second force be Y
Both the forces are perpendicular, so α = 90°
The resultant R of the two forces = 100N
Angle between resultant and 1 force, α = 60°
We know,
R² = X² + Y² + 2XYcos 90
100² = X² + Y²
If X makes an angle of Φ = 60°
Then, tan Ф = Y sin α / X + Y cos α
Putting the values we find,
tan 60 = Y/X
Y = √3X
Putting Y = √3X in equation 1 we get,
(X)² + (√3X)² = 100 X 100
4X² = 100 X 100
X² = 2500
X = 50N
Therefore, magnitude of the force = 50N
