Answer: 115m. Displacement can be taken from the distance between the initial point and the final point. In this case,the displacement is 115m.
Answer:
31.25 year .
Explanation:
The thickness of layer must change so the destructive interference may be converted into constructive interference . This can happen if thickness is reduced by λ /4 , so that path difference changes by 2 x λ /4 = λ /2 .
This will convert destructive to constructive interference.
change in thickness required = λ /4
= 525 / 4 nm
= 131.25 nm .
year required to wear off
= 131.25 / rate of decay
= 131.25 / 4.2
= 31.25 year .
<h3>
Answer:</h3>
5.5 N
<h3>
Explanation:</h3>
<u>We are given;</u>
- Real weight of an object in air as 10 N
- Apparent weight in water as 7 N
- Relative density of a liquid is 1.5
We need to calculate the apparent weight when in liquid .
- First we calculate upthrust
Upthrust = Real weight - Apparent weight
= 10 N - 7 N
= 3 N
- Then calculate the upthrust in the liquid.
we need to know that;
Relative density of a liquid = Upthrust in liquid/Upthrust in water
Therefore;
1.5 = U ÷ 3 N
Upthrust in liquid = 3 N × 1.5
= 4.5 N
- Therefore, the upthrust of the object in the liquid is 4.5 N
But, Upthrust = Real weight - Apparent weight
Therefore;
Apparent weight in Liquid = Real weight - Upthrust
= 10 N - 4.5 N
= 5.5 N
Thus, the weight when the object is immersed in the liquid is 5.5 N
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