Answer:
The distance of the object to the center of the earth increases.
Explanation:
The acceleration due to gravity on Earth is given by:
where
G is the gravitational constant
M is the Earth's mass
r is the distance of the object from the Earth's centre
We notice that:
- g does not depend on the mass of the object
- g is inversely proportional to r
This means that if the distance of the object from the Earth's centre increases, g decreases. So, the correct option is
The distance of the object to the center of the earth increases.
<h3><u>Answer;</u></h3>
the north end to the south end.
<h3><u>Explanation;</u></h3>
- Magnetic field lines from a bar magnet form lines that are closed. The direction of magnetic field is taken to be outward from the North pole of the magnet and in to the South pole of the magnet.
- A magnetic field refers to the area surrounding a magnet where a force is exerted on certain objects. These lines are spread out of the north end of the magnet.
- The magnetic field lines resemble a bubble.
Answer:
The frequency will decrease by a factor of square root of 2 (<em>ω = √(2 (g / L))</em>.
Explanation:
A simple pendulum consists of a mass m hanging from a string of length L and fixed at a pivot point P. When displaced to an initial angle and released, the pendulum will swing back and forth with periodic motion. By applying Newton's second law for rotational systems, the equation of motion for the pendulum may be obtained
τ = I α ⇒ - mg sin(θ) L = mL² (d²θ/dt²)
where
- τ is torque
- I is the moment of inertia
- α is the angular frequency
- g is the acceleration due to gravity
- L is the length of the string
- m is the mass of the ball
The above expression can be rearranged as
(d²θ/dt²) + g / L (sin(θ)) = 0
If the amplitude of angular displacement is small enough that the small angle approximation () holds true, then the equation of motion reduces to the equation of simple harmonic motion
(d²θ/dt²) + g / L (θ) = 0
The simple harmonic solution is
θ(t) = θ₀ cos(ωt + Ф)
where
- ω is the frequency of the pendulum
- Ф is the phase angle
The frequency is expressed as
ω = √(g / L)
If the pendulum is pulled from equilibrium by 2 times theta, The simple harmonic solution will be
θ(t) = θ₀ cos(2 ωt + Ф)
and therefore,<em> the frequency will be</em>
<em>ω = √(2 (g / L))</em>
Answer:
healthful I think! Hope that helped