Answer:
C. H2O is the base and H3O+ is the conjugate acid
Explanation:
According to Bronsted-Lowry acid-base theory, an acid is a substance that loses an hydrogen ion or proton (H+) while a base is a substance that gains an hydrogen ion (H+) or proton. Furthermore, this theory states that, the molecule formed when an acid donates its proton is called the CONJUGATE BASE, while the molecule formed when the base accepts proton is called CONJUGATE ACID.
In this question, the following equation is given:
NH4+(aq) + H2O(aq) ⇌NH3(aq) + H3O+ (aq)
Water (H2O) is the base in this equation because according to Bronsted-Lowry acid-base theory, it accepts an hydrogen ion (H+) while hydroxonium ion (H3O+) is the conjugate acid.
When the temperature increases, the kinetic energy of the particles increase this inturn makes them vibrate
Answer:
![\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20molarity%20%3D%200.17%20%5C%20M%20%5C%20C_6H_12O_6%7D%7D)
Explanation:
Molarity is found by dividing the moles of solute by liters of solution.
![molarity = \frac {moles}{liters}](https://tex.z-dn.net/?f=molarity%20%3D%20%5Cfrac%20%7Bmoles%7D%7Bliters%7D)
We are given grams of a compound and milliliters of solution, so we must make 2 conversions.
1. Gram to Moles
We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.
- C: 12.011 g/mol
- H: 1.008 g/mol
- O: 15.999 g/mol
Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.
6(12.011)+12(1.008)+6(15.999)=180.156 g/mol
Use this number as a ratio.
![\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}](https://tex.z-dn.net/?f=%5Cfrac%20%7B180.156%20%5C%20g%5C%20C_6H_12%20O_6%7D%7B%201%20%5C%20mol%20%5C%20C_6H_12O_6%7D)
Multiply by the given number of grams.
![78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}](https://tex.z-dn.net/?f=78%20%5C%20g%20%5C%20C_6H_12O_6%20%2A%5Cfrac%20%7B180.156%20%5C%20g%5C%20C_6H_12%20O_6%7D%7B%201%20%5C%20mol%20%5C%20C_6H_12O_6%7D)
Flip the fraction and divide.
![78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}](https://tex.z-dn.net/?f=78%20%5C%20g%20%5C%20C_6H_12O_6%20%2A%5Cfrac%20%7B%201%20%5C%20mol%20%5C%20C_6H_12O_6%7D%7B180.156%20%5C%20g%5C%20C_6H_12%20O_6%7D)
![\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6](https://tex.z-dn.net/?f=%5Cfrac%20%7B%2078%20%5C%20mol%20%5C%20C_6H_12O_6%7D%7B180.156%20%7D%3D%200.432958102977%20%5C%20mol%20%5C%20C_6H_12O_6)
2. Milliliters to Liters
There are 1000 milliliters in 1 liter.
![\frac {1 \ L }{ 1000 \ mL}](https://tex.z-dn.net/?f=%5Cfrac%20%7B1%20%5C%20L%20%7D%7B%201000%20%5C%20mL%7D)
Multiply by 2500 mL.
![2500 \ mL* \frac {1 \ L }{ 1000 \ mL}](https://tex.z-dn.net/?f=2500%20%5C%20mL%2A%20%5Cfrac%20%7B1%20%5C%20L%20%7D%7B%201000%20%5C%20mL%7D)
![2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L](https://tex.z-dn.net/?f=2500%20%2A%20%5Cfrac%20%7B1%20%5C%20L%20%7D%7B%201000%20%7D%3D%202.5%20%5C%20L)
3. Calculate Molarity
Finally, divide the moles by the liters.
![molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}](https://tex.z-dn.net/?f=molarity%20%3D%20%5Cfrac%20%7B0.432958102977%20%5C%20mol%20%5C%20C_6H_12O_6%7D%7B%202.5%20%5C%20L%7D)
![molarity = 0.173183241191 \ mol \ C_6H_12O_6/L](https://tex.z-dn.net/?f=molarity%20%3D%200.173183241191%20%5C%20mol%20%5C%20C_6H_12O_6%2FL)
The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.
![molarity \approx 0.17 \ mol \ C_6H_12O_6 /L](https://tex.z-dn.net/?f=molarity%20%5Capprox%200.17%20%5C%20mol%20%5C%20C_6H_12O_6%20%2FL)
1 mole per liter is also equal to 1 M.
![molarity = 0.17 \ M \ C_6H_12O_6](https://tex.z-dn.net/?f=molarity%20%3D%200.17%20%5C%20M%20%5C%20C_6H_12O_6)
Mostly pollution. It combines with water vapor in clouds to make sulfuric acid.
Answer:
density
Explanation:
Density is an important measurement. It has an unit: g/mL or kg/L, ...
Evaporation, freezing, melting are the processes in which the substances change their states. Other processes are: condensation, sublimation, deposition.
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Hope this answer can help you. Have a nice day!