Answer
given,
v = (6 t - 3 t²) m/s
we know,
position of the particle
integrating both side
x = 3 t² - t³
Position of the particle at t= 3 s
x = 3 x 3² - 3³
x = 0 m
now, particle’s deceleration
a = 6 - 6 t
at t= 3 s
a = 6 - 6 x 3
a = -12 m/s²
distance traveled by the particle
x = 3 t² - t³
at t = 0 x = 0
t = 1 s , x = 3 (1)² - 1³ = 2 m
t = 2 s , x = 3(2)² - 2³ = 4 m
t = 3 s , x = 0 m
total distance traveled by the particle
D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s
D = 2 + 4 + 2 = 8 m
average speed of the particle
Answer:
Initial Velocity = 0 m/s
Final Velocity = 34.6 m/s
time = 3.5 s
Explanation:
The initial velocity must be zero since, the egg must be at rest initially, before dropping.
<u>Initial Velocity = 0 m/s</u>
Now, for time we use 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = Height = 61 m
Vi = Initial Velocity = 0 m/s
g = 9.8 m/s²
t =time = ?
Therefore,
61 m = (0 m/s)(t) + (1/2)(9.8 m/s²)t²
t² = (61 m)(2)/(9.8 m/s²)
t = √(12.45 s²)
<u>t = 3.5 s</u>
Now, for final velocity we will use 1st equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(3.5 s)
Vf = 34.6 m/s
Answer:
I think the right answer is option B.
Answer:
1500 Joules
Explanation:
Work = Force x Distance
When multiplying by 10 you simply shift all the digits to the
left and append a 0 to the end.
so 150 x 10 = 1500 Joules
