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Elenna [48]
4 years ago
14

A 0.25-kg ball attached to a string is rotating in a horizontal circle of radius 0.5 m twice every second, what is the tension i

n the string
Physics
1 answer:
Svetradugi [14.3K]4 years ago
3 0

Answer:

T = 19.75 N

Explanation:

given,

mass of ball = 0.25 Kg

radius = 0.5 m

frequency = 2 s⁻¹

tension in the string = ?

angular velocity

ω = 2 π f

ω = 2 π x 2

ω = 12.57 rad/s

tension on the string is equal to the centripetal force

T = m ω² r

T = 0.25 x 12.57² x 0.5

T = 19.75 N

Tension in the string is equal to T = 19.75 N

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The energy transferred by the appliance using mains electricity is 17.3 KJ

<h3>Data obtained from the question </h3>
  • Potential difference (V) = 230V
  • Charge (Q) = 150 C
  • Energy (E) =?

<h3>How to determine the energy transferred </h3>

The energy transferred can be obtained as follow:

E = ½QV

E = ½ × 150 × 230

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Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

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Friction force,f=\mu_rmg=0.007\times 60\times 9.8=4.1 N

Where g=9.8 m/s^2

Let speed of cyclist=v'

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Density of air,\rho_{air}=1.225 kg/m^3

F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N

Power,P=(F_d+f)\times v'

340=(4.1+4.635) v'=8.735v'

v'=\frac{340}{8.735}=38.9m/s

v'=87.1 mph

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