Complete question:
A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.
Answer:
2.0N
Explanation:
Given that,
Mass, m of the frog = 0.5 kg
The acceleration of the frog = 4.0 m/s².
We have been asked To find,
The magnitude of the net force exerted on the frog as it leaps.
So
We calculate this using the formula below :
F = ma
When we insert the values into the formula, we have:
F = 0.5 kg × 4 m/s²
F = 2.0 N
Therefore, the magnitude of net force is 2.0 N.
Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion.
The speed of light : 299 792 458 m / s
Answer:
E = 4.75 x 10⁻¹⁶ J
Explanation:
given,
wavelength of the x-ray , λ = 4.18 Å
Energy of photon = ?
we know
where h is the planks constant
c is the speed of light
h = 6.626 x 10⁻³⁴ m² kg / s
c = 3 x 10⁸ m/s
now,
E = 4.75 x 10⁻¹⁶ J
hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J
Answer:
The net force is zero because both volleyball players are hitting the ball with same force.
Explanation:
