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Anarel [89]
3 years ago
12

Summer sausage is element

Chemistry
1 answer:
RoseWind [281]3 years ago
5 0
???
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How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions
omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

5 0
3 years ago
One brand of vinegar has a pH of 4.5. Another brand has a pH of 5.0. The equation for the pH of a substance is pH = –log[H+], wh
grigory [225]
[H+] in first brand:
4.5 = -log([H+])
[H+] = 10^(-4.5)

[H+] in second brand:
5 = -log[H+]
[H+] = 10^(-5)

Difference = 10^(-4.5) - 10^(-5)
= 2.2 x 10⁻⁵

The answer is A.
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3 years ago
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2. Because a cumulonimbus cloud is a towering vertical cloud
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These celestial bodies are thought to originate from two different sources. Some are called long-period and originate from the O
Alexus [3.1K]
It’s c I believe because it says 209 years to complete an orbit so hint yourself ?.....
6 0
2 years ago
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Find the molecular mass of.
Margaret [11]

Answer:

  1. sodium oxide Nao
  2. aluminum chloride Al2cl3
  3. sodium sulphate Naso4
  4. <em>magnes</em><em>ium</em><em> </em><em>hydroxide</em><em> </em><em>Mgoh2</em>
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