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Anarel [89]
3 years ago
12

Summer sausage is element

Chemistry
1 answer:
RoseWind [281]3 years ago
5 0
???
Whats the question?
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What is the difference between parent material
Naily [24]
I don’t understand the question
4 0
4 years ago
HELP!!!!!!!!!!!!!!!! PRETTY PLEASE !!!!!!!!!!!!!!!!
I am Lyosha [343]

Answer:

B. 75.0 kPa

Explanation:

P1V1/T1=P2V2/T2

(x * 100 L)/(300 K)=(100 kPa * 50.0 L)/(200 K)

x=75.0 kPa

4 0
4 years ago
Read 2 more answers
Compare the models of the superconductor to the CaTiO3 models. What similarities and differences do you notice? How do the coord
bulgar [2K]

Answer:

Compare the models of the superconductor to the CaTiO3 models.

What similarities and differences do you notice?

The differences are in the crystal structure unit cell, consisting of five atoms  with calcium atoms at the corners, a titanium atom at the center and oxygen at centers forming an octahedron, and the similarities are in the HTSC cuprates structures.

How do the coordination numbers of the central ions compare?

The Ca+2 cation layers are insulating and donate electrons to the CuO2 planes. The Sro layers are barriers, isolate groups of CuO2 planes from each other, the ca2 and bi2 are charge reservoir layers.

Explanation:

Allow the current to flow without resistence or interruption, through a superconductor material at room temperature, is still a not fullfilled dream in the superconductivity research.

Transition temperatures (Tc) achieving though, have opened the options for many applications, high temperature superconductors are now the main researchs´ focusing, known as perovskites, which are simply ceramics, such as yttrium barium copper oxides (YBCOs) or 1-2-3 compounds and the bismuth strontium calcium copper oxide (BSCCOs) or Pb-BSCO (PBSCCO) are the best insulators known at room temperature, and at liquid nitrogen temperature, the become perfectly superconducting.

The discovery of superconducting transition at 35 K in lanthanum barium copper oxide ceramic system- La2-xBaxCuO4 and the 92 K for 123 systems made a difference among them as these systems contained rare-earth elements.

A great step was gained with the discovery of the first high temperature (Tc) oxide ceramic system, based on Bi-Sr-Cu-O perovskite, which did not have any rare-earth component, followed by several discoveries of these rare-earth free systems, such as the Bi-Sr-Cu-O, which increased Tc to 85 K adding calcium, Br-Sr-Ca-Cu-O system which reached 110 K; Ti-Ba-Ca-Cu-O system which reached a Tc of 125 K, but the Bi systems synthesis and rare-earth systems as YBCO differ in simplicity and getting a monophase superconducting phase is still not fullfilled.

Varying elemental ratios and dopants such as Pb, and so forth has given only partial success, even the Bi compositions which showed to have monophase in Bi systems, reproducibility controlling elemental ratios cause a high percentage of inaccuracy.

In comparisson with the conventional solidstate sintering technique, the glassy precursor route is more efficient and realizable to achieving superconducting monophase with rareearth free BSCCO perovskites or Bi perovskites, with interesting parameters and optimizing factors.

YBCO gave the highest Tc ever in 1987, easy to synthesize and good phase stability, bismuth-based cuprates gave a Tc of 110 Kc, Thalium-based cuprates gave a Tc of 120 to 125 K and mercury-based cuprates that gets a Tc of 135 K, which created a new hope for HTSC based on cuprates.

Most of the known cuprate superconductors belong to a single structural familiy closely realted to each other.

Bistmuth-based cuprates are good HTSC as their grain alignment is along the c-axis, which increases the critical current.

Bi-Sr-Ca-Cu-O

   

8 0
4 years ago
3. 79.0 grams of water was produced with a percent yield of 75.0%. How many grams of
Alex Ar [27]

Answer:

Explanation:

3 )

18 grams of water contains 16 grams of oxygen .

Let the grams of oxygen needed be m .

yield is 75%

Only 75 % of m will make water .

.75 m will form water .

water formed by .75 m of oxygen = 18 / 16 x .75 m

Given that

18 / 16 x .75 m = 79

m = (16 x 79) / ( 18 x .75 )

= 93.63 grams .

So oxygen required is 93.63 grams .

4 )

One mole of water contains 0.5 moles of oxygen.

2 moles of oxygen will make 2 /,5 = 4 moles of water .

percent yield is 82 % ,

so water produced = .82 x 4 = 3.28 moles of water.

7 0
3 years ago
What is the balanced chemical equations for fe + o2 → iron(౹౹) oxide?
pishuonlain [190]
The idea behind balancing chemical equations is that the number of atoms an element has on the reactants' side must be equal to the number of atoms it has on the products' side.

These atoms will become a part of different compounds once the reaction is completed, but they must always be in equal numbers on both sides.

So, look at iron first. One atom reacts, but two are produced - notice the 2 subscript iron has in Fe2O3. This means you must double the number of atoms on the reactants' side to reach an equality.

2Fe(s)+O2(g)→Fe2O3(s)

Now look at oxygen. Two atoms react, but three are produced. The trick here is to find a common multiple that will make the number of atoms equal on both sides.

The easiest way to do this is to multiply the atoms that react by 3, which will give you 6 oxygen atoms that react, and the atoms that are produced by 2 - this will get you 6 oxygen atoms produced.

2Fe(s)+3O2(g)→2Fe2O3(s)

However, notice that the iron atoms are unbalanced again. You have 2 that react, but 4 that are produced → multiply the atoms that react by 2 again, which will give you

4Fe(s)+3O2(g)→2Fe2O3(s)

3 0
4 years ago
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