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Shalnov [3]
3 years ago
6

The second-order diffraction for a gold crystal is at an angle of 22.20o for X-rays of 154 pm. What is the spacing between the c

rystal planes?
Chemistry
1 answer:
Alenkinab [10]3 years ago
4 0

<u>Answer:</u> The spacing between the crystal planes is 4.07\times 10^{-10}m

<u>Explanation:</u>

To calculate the spacing between the crystal planes, we use the equation given by Bragg, which is:

n\lambda =2d\sin \theta

where,

n = order of diffraction = 2

\lambda = wavelength of the light = 154pm=1.54\times 10^{-10}m     (Conversion factor:  1m=10^{12}pm )

d = spacing between the crystal planes = ?

\theta = angle of diffraction = 22.20°

Putting values in above equation, we get:

2\times 1.54\times 10^{-10}=2d\sin (22.20)\\\\d=\frac{2\times 1.54\times 10^{-10}}{2\times \sin (22.20)}\\\\d=4.07\times 10^{-10}m

Hence, the spacing between the crystal planes is 4.07\times 10^{-10}m

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3 years ago
Why does magnesium oxide have a high melting point?
Mandarinka [93]

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__________________________________________

Now lets look at the ionic bonding between magnesium and oxygen:

In the outer shell of Magnesium, there are 2 electrons.

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Since Magnesium lost the two electrons, it's second shell (which has 8 eletrons) now becomes the outer shell. So Magnesium also now has a full outer shell. But since it has lost two electrons, it becomes a positively charged ion with a charge of + 2.

The positive Magnesium ion and negative Oxygen ion and now strongly attracted to each other, and form a strong ionic compound (magnesium oxide) with a lattice structure.

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3 years ago
A certain solution is 70% ethanol and the rest being distilled water. If there are 12 moles of ethanol per litre of solution, fi
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Answer:

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Explanation:

Hello there!

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Read 2 more answers
Consider the following generic reaction for which Kp = 5.51 × 105 at 25°C:
lora16 [44]

Answer:

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Explanation:

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K_p= K_c\times (RT)^{\Delta n}

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For the first equilibrium reaction:

2R_{(g)}+A_{(g)}\rightleftharpoons2Z_{(g)}

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T = (25 + 273.15) K = 298.15 K  

R = 0.082057 L atm.mol⁻¹K⁻¹

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5.51\times 10^5= K_c\times (0.082057\times 299)^{-1}

K_c\frac{1}{24.535043}=551000

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3 years ago
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