The field strength needed to produce a 24.0 V peak emf is 0.73T.
To find the answer, we need to know about the expression of emf.
What's the expression of peak emf produced in a rotating rectangular loops?
- The peak emf produced in a rotating loops= N×B×A×w
- N= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequency
- So, B = emf/(N×A×w)
<h3>What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?</h3>
- N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²
- Emf= 24V, w= 2π×400 rpm= 2π×(400rps/60) = 42 rad/s
- Now, B= 24/(300×0.00261×42)
B= 24/(300×0.00261×42) = 0.73T
Thus, we can conclude that the magnetic field is 0.73T.
Learn more about the electromagnetic force here:
brainly.com/question/13745767
#SPJ4
Answer:
22 N applied force
Explanation: Since they are both pushing the wagon in the same direction the force adds up.
I’m pretty sure the answer is C. Any change of state or movement requires energy
Answer:
Newton's second law of motion describes the relationship between force and acceleration. They are directly proportional. If you increase the force applied to an object, the acceleration of that object increases by the same factor. In short, force equals mass times acceleration.
Explanation:
Answer:
F=1.14N j
Explanation:
The magnitude of the magnetic force over a charge in a constant magnetic field is given by the formula:
(|)
In this case v and B vectors are perpendicular between them. Furthermore the direction of the magnetic force is:
-i X k = +j
Finally, by replacing in (1) we obtain:
hope this helps!
