The given question is incomplete. The complete question is as follows.
The solubility of in water is 208 g per 100 g of water at . A solution of in water at is formed by dissolving 322 g in 100 g water. When this solution is slowly cooled to , no precipitate forms. At equilibrium, what mass of crystals do you expect to form?
Explanation:
The given data is as follows.
Solubility of in 100 g of water = 208 g (at )
Amount of in 100 g of water = 322 g (at )
At equilibrium, the mass of crystals formed is calculated as follows.
Mass of crystal = Mass of at - Mass of
Putting the given values into the above formula, mass of the crystals will be calculated as follows.
Mass of crystal = Mass of at - Mass of
= 322 g - 208 g
= 114 g
Thus, we can conclude that crystals formed is 114 g.