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navik [9.2K]
2 years ago
14

Which statement is true about the concentration of the reactants and products in chemical equilibrium?

Chemistry
1 answer:
bulgar [2K]2 years ago
5 0

Answer:

Ans: 2

Explanation:

The concentration of reactants and the concentration of products are constant.  

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An industrial chemist is studying a sample of an unknown metal. Describe two ways he could change the metal physically and two w
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Answer:

Some of the physical changes used by the industrial chemist in order to identify it is by scratching it with other metals in order to find the hardness of it. Trying to deform it in order to find the malleability, and to heat it and measure the temperature in order to find the melting point.  

Some of the chemical changes used by the industrial chemist in order to identify it is by inserting it in water to observe that whether it reacts with it or not, if the reaction is violent, then the metal belongs to either group I or group II. The other method is to insert it in acids of distinct strength and to observe its reaction. The metals belonging to the second group react briskly with acids. The other metals react gradually with acids and others are almost inert.  

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2 years ago
Which state of matter undergoes changes in volume most easily
AlladinOne [14]
Solid should be the anwser
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3 years ago
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How many moles are in 8.11 X 1020 molecules of CH4?<br> &lt; &gt;
Gre4nikov [31]

Answer:

6.022⋅1023

Explanation:

4 0
3 years ago
Fossils can be body parts of ancient organisms, or they can be traces. Give five examples of traces. Help this is due today!!!!!
SSSSS [86.1K]

Burrows, tracks, coprolites, nests and footprints are examples of traces that can be found in a fossil.

6 0
3 years ago
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibrium described by the equation N2O4(g)
lora16 [44]

<u>Answer:</u> The value of equilibrium constant is 0.997

<u>Explanation:</u>

We are given:

Percent degree of dissociation = 39 %

Degree of dissociation, \alpha = 0.39

Concentration of N_2O_4, c = \frac{1mol}{1L}=1M

The given chemical equation follows:

                     N_2O_4\rightleftharpoons 2NO_2

<u>Initial:</u>                c             -

<u>At Eqllm:</u>         c-c\alpha      2c\alpha

So, equilibrium concentration of N_2O_4=c-c\alpha =[1-(1\times 0.39)]=0.61M

Equilibrium concentration of NO_2=2c\alpha =[2\times 1\times 0.39]=0.78M

The expression of K_{c} for above equation follows:

K_{c}=\frac{[NO_2]^2}{[N_2O_4]}

Putting values in above equation, we get:

K_{c}=\frac{(0.78)^2}{0.61}\\\\K_{c}=0.997

Hence, the value of equilibrium constant is 0.997

4 0
2 years ago
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