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gayaneshka [121]
3 years ago
5

Find the freqency of a wave with a period of 0.5 seconds

Physics
1 answer:
never [62]3 years ago
8 0

Answer: Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second. In this case, there is 1 cycle per 2 seconds. So the frequency is 1 cycles/2 s = 0.5 Hz.

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After three shuttle accidents in three months, one of which resulted in a critical injury to a driver, Get Around Shuttle driver
alexandr1967 [171]

Answer:

Safety

Explanation:

As we know that safety is very important before doing anything .This is also a important part of the human needs.Every human wants both emotional and physical safety from his job or whatever is doing.

Maslow's given a Hierarchy of Needs and the second tier of this Hierarchy is safety.

So the answer of the given question is safety.

7 0
4 years ago
You are viewing a read out of an oscilloscope that shows you when different voltages in a circuit maximize. If the period of the
Aleksandr-060686 [28]

Answer:

The time is  t = 0.02 \ s  

Explanation:

From the question we are told that

  The period of the circuit is  T  =  0.04

Generally voltage maximization of the capacitor occurs during the voltage minimization of the inductor and vise versa

So the time between the voltage maximization of the capacitor and that of the inductor is mathematically represented as

           t = \frac{T}{2}

=>        t = \frac{0.04}{2}

=>        t = 0.02 \ s  

7 0
3 years ago
A 3.30 x 10-2-kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring const
avanturin [10]

Answer:

0.17547 m

Explanation:

m = Mass of block = 3.3\times 10^{-2}\ kg

v = Velocity of block = 10.8 m/s

k = Spring constant = 125 N/m

A = Amplitude

The kinetic energy of the system is conserved

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow \\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{3.3\times 10^{-2}\times 10.8^2}{125}}\\\Rightarrow A=0.17547\ m

The amplitude of the resulting simple harmonic motion is 0.17547 m

6 0
3 years ago
A bus travelling 30.0 km/h east has a constant increase in speed of 1.5 m/s. What is its velocity 6.8s later
alekssr [168]

Answer:

8.72 seconds before

Explanation:

and 27.1 secs after

7 0
3 years ago
When landing after a spectacular somersault, a 35.0 kg gymnast decelerates by pushing straight down on the mat. calculate the fo
Sliva [168]

The deceleration experienced by the gymnast is the 9 times of the acceleration due to gravity.

Now from Newton`s  first law, the net force on gymnast,

F_{net} =F-W=ma

Here, W is the weight of the gymnast and a is the acceleration experienced by the gymnast (9\times g acceleration due to gravity)  

Therefore,

F= ma+W OR F=ma+mg=m(g+a)

Given m = 30 kg anda=9\times g=9\times 9.8 m/s^{2} =88.2 m/s^{2}

Substituting these values in above formula and calculate the force exerted by the gymnast,  

F=(40 kg) (88.2 m/s^{2} +9.8 m/s^{2} )

F=3.537\times10^{3}N

6 0
3 years ago
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