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Rus_ich [418]
3 years ago
8

Solve the equation. 5x-5=10x+2

Physics
2 answers:
Veronika [31]3 years ago
8 0

Answer:

x = - 1.4

Explanation:

-5=10x+2-5x     (subtract 5x from both sides)

-5=5x+2     (simplify)

-5-2=5x     (subtract 2 from both sides)

-7=5x      (simplify)

x=-7/5     (divide both sides by 5)

x=-1.4    (simplify)

i would really appreciate getting a brainliest. anyways i hope this helped and have a great rest of your day/night!! :)

murzikaleks [220]3 years ago
5 0
5x-5=10x+2

5x-5x-5=10x-5x+2

-5-2=5x+2-2

-7/5=5x/5

x=-7/5
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jenyasd209 [6]

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2 years ago
A 0.0427 kg racquet-ball is moving
Gwar [14]

Answer:

Mass of the box = 0.9433 kg

Explanation:

Mass of racket-ball (m_1) = 0.00427 kg

Velocity of racket-ball before collision (v_{1i}) = 22.3 m/s

Velocity of racket-ball after collision with box (v_{1f}) = -11.5 m/s

[Since ball is bouncing back, so velocity is taken negative.]

Velocity of the box before collision v_{2i} = 0 m/s

<em>[Since the box is stationary, so velocity is taken zero]</em>

Velocity of box moving forward after collision v_{2f}= 1.53 m/s

To find the mas of the box m_2.

By law of conservation of momentum we have:

Momentum before collision = Momentum after collision

This can be written as:

p_i=p_f

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

We can plugin the given value to find m_2

(0.0427\times 22.3)+(m_2\times 0)=(0.0427\times (-11.5))(m_2\times 1.53)

0.9522+0=-0.4911+1.53m_2

Adding both sides by 0.4911

0.9522+0.4911=-0.4911+0.4911+1.53m_2

1.4433=1.53m_2

Dividing both sides by 1.53.

\frac{1.4433}{1.53}=\frac{1.53m_2}{1.53}

0.9433=m_2

∴ m_2=0.9433 kg

Mass of the box = 0.9433 kg (Answer)

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2 years ago
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The correct answer is 4.

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