Gaussian surfaces A and B enclose the same positive point charge. The area of surface A is two times larger than that of surface
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The moment of inertia of the flywheel is 2.63 kg-
It is given that,
The maximum energy stored on the flywheel is given as
E=3.7MJ= 3.7× J
Angular velocity of the flywheel is 16000 = 1675.51
So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :
E =
By rearranging the equation:
I =
I = 2.63 kg-
Thus the moment of inertia of the flywheel is 2.63 kg-.
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