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s2008m [1.1K]
3 years ago
13

Why is it a good idea to start with room temperature water in the calorimeter?

Physics
2 answers:
densk [106]3 years ago
8 0

Explanation:

It is a good idea to start with room temperature water in the calorimeter because the room temperature water helps to determine the heating up/cooling down because of the environment as the experiment takes place. Because the calorimeter heat is the same as the heat of the water.

jeka57 [31]3 years ago
6 0

Answer:

it a good idea to have room temperature water in calorimeter because it has a high specific heat it is non-flammable, it can be measured easily, it is affordable and it can retain the heat for longer time.

Explanation:

For several reasons water at room temperature is used in the calorimeter.

  • High Specific Heat

It can store high amount of heat with low rise in temperature. It can store heat for longer time which allows the material in the calorimeter to absorb that heat.

  • High range of Freezing and Boiling point

It has a huge rage between its freezing point and its boiling point and thus we  can measure a large range of temperature without its phase change.

  • Abundance

Water is a pure compound available in abundance with ease.

  • Definition

According to the definition, one calorie is the amount of energy required by one gram of water to raise its temperature by one degree Celsius. Therefore water plays a vital role in calorie measurement.

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A 4kg block and a 2kg block can move on horizontal frictionless surface. The blocks are accelerated by a +12-N force that pushes
Stolb23 [73]

Answer:

a) -4 N

b) +4 N

Explanation:

Draw a free body diagram for each block.

For the large block, there are 2 forces: 12 N pushing to the right, and F pushing to the left.

For the small block, there is 1 force, F pushing to the right.

There are also weight and normal forces in the vertical direction, but we can ignore those.

Sum of forces on the large block in the x direction:

∑F = ma

12 − F = 4a

Sum of forces on the small block in the x direction:

∑F = ma

F = 2a

2F = 4a

Substitute:

12 − F = 2F

12 = 3F

F = 4

The small block pushes on the large block 4 N to the left (-4 N).

The large block pushes on the small block 4 N to the right (+4 N).

4 0
3 years ago
Red clothes will---the red light.A)Reflect B)refract C)Absorb D)transmission E)Dispersion
posledela

Red clothes look red  because they REFLECT the red light, and absorb light of other colors.

7 0
2 years ago
g The electric power needs of a community are to be met by windmills with 40-m-diameter rotors. The windmills are to be located
Ksenya-84 [330]

Answer:

Explanation:

Given Data

The diameter of the wind mills is d = 40m

Velocity of the air is V = 6 m / s

Required power output is:  P ₀ = 2100 k W

Expression to calculate the exergy of the air is

E = V ² / 2

Substitute the value in above expression

E = ( 6 m / s ) ² / 2

E = 18 m ² / s ² x (1kJ/kg / 1000m²/s²)

E = 0.018 k J / k g

Expression to calculate the density of the air is

P v =m R T

m /v = P  /RT ⋯ ⋯( I )

Here  

m  is the mass of the air,  

v  is the volume of the air,  

P  is the atmospheric pressure,  

T  is the standard temperature at the atmospheric pressure and  

R  is the gas constant

As the density is

ρ = m /V

Substitute the value in expression (I)

ρ = 101  kP a /( 0.287 k J / k g ⋅ K ) ( 298 K )

ρ = 1.180 k g / m ²

Expression to calculate the mass flow rate is

m = ρ A V ⋯ ⋯ ( I I )

Here  A  is the area of the windmill

Expression to calculate the  A  is

A = π /4  d ²

Substitute the value in above expression

A = π /4 ( 40 m ²)

A = 1256.63 m ²

Substitute the value in expression (II)

m = ( 1.180 k g / m ³) ( 1256.63 m ²) ( 6 m / s )

m = 8896.94  k g / s

Expression to calculate the maximum power available to the windmill is

P w = m ( V ² /2 )

Substitute the value in above expression

P w = 8896.94  k g / s ( (6m/s)²/2 )

P w = 160144.92 W  × ( 1 W /1000 k W )

P w = 160.144 k W

Expression to calculate the number of windmills required is

n = P o /P w

Substitute the value in above expression

n=2100kw/160.144kw

n=13.11

8 0
3 years ago
There are two main groups of recyclable material,
Illusion [34]

Answer:Paper and plastic!

Explanation:

3 0
2 years ago
Frank has a paperclip. It has a mass of 12g and a volume of 3cm3. What is its density?​
Mkey [24]

Answer:

D = 4 g/cm³

Explanation:

Density = Mass / Volume

Step 1: Define

D = x

M = 12 g

V = 3 cm³

Step 2: Substitute

D = 12g/3 cm³

Step 3: Simplify

D = 4g / cm³

4 0
2 years ago
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