The magnitude of the electric force on the charge is 5 N.
<h3>Magnitude of force on the charge</h3>
The magnitude of force on the charge is calculated as follows;
F = Eq
where;
- E is electric field
- q is magnitude of the charge
F = 100 N/C x 0.05 C
F = 5 N
Thus, the magnitude of the electric force on the charge is 5 N.
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First figure out how many atoms you have with Avogadro's number. Since there are 63.5 grams/mol and you have 50.6 grams, you have (50.6/63.5)6.022E23=4.7986E23 atoms. Since there are 29 protons per atom, there are also 29 electrons per atom, so you should have a total of
29*4.7986E23=1.3916E25 electrons.
Since there is a positive charge you know some of these electrons are missing. How many are missing can be found by dividing the charge you have by the charge on the electron: 1.6E-6/1.6022E-19 = 9.98627E12 electrons are missing.
Now take the ratio of what is missing to what there should be:
9.98627E12/1.3916E25 = 7.1760873E-13
If the sunlight is covered up by clouds or other things the temperature will be a little cooler, because the sun rays arent hitting things and making them warmer<span />
Given
v = 343 m/s
ac = 5g
ac = 5*9.8 m/s^2
ac = 49 m/s^2
where,
v: velocity
ac = centripetal aceleration
Procedure
We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration ac; centripetal means “toward the center” or “center seeking”.
Formula
The minimum radius not to exceed the centripetal acceleration is 2401 m.
