Question

We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 4.2 g. Find the number of atoms in a nickel coin. Each mole (6.02 × 1023 atoms) has a mass of about 57.8 g. Answer in units of atoms

Answer 1

Answer:

The number of atoms is $N = 4.37*10^{22} \ atoms$

Explanation:

From the question we are told that

                 The mass of coin  is $m_n = 4.2g$

                   Number of atom in one mole = $n =6.02*10^{23} \ atoms$

                   Molar mass of nickel $M = 57.8g$

Now the relation to obtain the number of atom in  the  nickel coin is

                        $N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel } * No\ of\atoms \ in \ \ one\ mole\ of\ nickel$

                           $= \frac{4.2}{57.8}* 6.02*10^{23}$

                           $=4.37 *10^{22} atoms$