Answer:
Explanation:
Tension T in the rope will create torque in solid cylinder ( axle ). If α be angular acceleration
T R = 1/2 M R²α ( M is mass and R is radius of cylinder )
= 1/2 M R² x a / R ( a is linear acceleration )
T = Ma / 2
For downward motion of the bucket
mg - T = m a ( m is mass and a is linear acceleration of bucket downwards )
mg - Ma / 2 = ma
a = mg / ( M /2 + m )
Substituting the values
a = 14.7 x 9.8 / ( 5.8+ 14.7 )
= 7 m / s²
A )
T = Ma / 2
= 5.8 x 7
= 40.6 N
B ) v² = u² + 2 a h
= 2 x 7 x 10.3
v = 12 m /s
C )
v = u + a t
12 = 0 + 7 t
t = 1.7 s
Answer:
The force is being pulled my the gravity or it could be a third party thing like a black hole you feel me
Explanation:
Answer:
The car will travel a distance of 17.45 meters.
Explanation:
Given:
Initial velocity
= 0
Final velocity
= 7.6 m/s
Time taken = 4.6 s
Acceleration = (Final velocity - Initial Velocity )/time

We have to calculate total distance traveled by the car.
Let the distance traveled be 'd'
Equation of motion:

Plugging the values.
⇒
⇒
⇒
The car will travel a distance of 17.45 meters for the above case.
Let
V the speed of the girl per step
v the speed of the escalator per step
L the length between ground and floor in number of steps
V*60+v*60=L => V+v=L/60
V*90-v*90=L => V-v=L/90
By adding the equations V+v=L/60 and V-v=L/90 we get:
2V=L(3+2)/180
V=5L/360
V = L/72
Time to climb (in steps) with v=0 (escalator standing still) is:
V*t=L
t = L/V
t = L/(L/72)
t =72 steps
The girl will count 72 steps.
W= 18*10^-3m
N= 18*710 ( because you have 710 slits per mm ) = 12780
lambda = 506*10^-9
The first step is to workout d.
d = w/N
d =18*10^-3m/12780
d =1.41*10^-6m
The second step is to work out the maximum number of m.
Since sin (theta) = less than 1, then m*lambda/d = less then 1,
therefore m= less than d/lambda
( I know thats confusing but trust me )
so m is less than 1.41*10^-6m/506*10^-9
= 2.7
Therefore use m = 2
Lastly put it all into the formula
dsin (theta) = m*lambda so:
theta = sin^-1(m*lambda/d)
theta = sin^-1(2*506*10^-9/1.41*10^-6m)
theta = 45.95 degrees or 46 degrees