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3 years ago

What is the wavelength of a wave with a frequency of 200Hz while traveling at 125.5m/s

Physics

1 answer:

nikdorinn [45]3 years ago

4 0

Answer:

0.6275 metres

Explanation:

v = fl

125.5 = 200 * wavelength

125.5 / 200 = wavelength = 0.6275m

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Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor

IgorC [24]

Answer:

A dissipates more power.

Explanation:

In a series circuit, the current is the same at any point in it.
The power dissipated in any resistor follows Joule's law, as follows:

$P = I^{2} * R$

So, for a given current, the power is directly proportional to the resistance of the resistor.
In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.

8 0

3 years ago

Unit of gravitational force

azamat

Answer:

Newton

Explanation:

9.80665 × kgf = 1 Newton N

1 kilogram force (kgf) was the force of gravity, which is pushing a mass of 1 kg at one place in the world on the ground; calculated according to Newton's law force = mass × acceleration.

3 0

3 years ago

Can someone help me plz

yKpoI14uk [10]

The height increases (c)

5 0

3 years ago

Alan starts from his home and walks 1.3 km east to the library. He walks an additional 0.68 km east to a music store. From there

zepelin [54]

Answer: final Displacement = 0 km, total distance covered =7 km

Explanation:

Given the following :

From home to library = 1.3 km East

Library to music store = 0.68km East

Music store to friend's house = 1.1km North

Friend's house to grocery store = 0.42 km North

Displacement is the net change in distance traveled.

Eastward distance :

To = (1.3 + 0.68)km = 1.98km East

Fro = (0.68 + 1.3)km = 1.98 km East

Δ distance = (1.98 - 1.98) = 0

Northward direction:

To = (1.1 + 0.42)km = 1.52km north

Fro = (0.42 + 1.1)km = 1.52km North

Δ distance = (1.98 - 1.98) = 0

Hence final Displacement = 0

Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5

= 7km

3 0

3 years ago

A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 14.413

natima [27]

Answer:

The value of charge q₃ is 40.46 μC.

Explanation:

Given that.

Magnitude of net force $F=14.413\ N$

Suppose a point charge q₁ = -3 μC is located at the origin of a co-ordinate system. Another point charge q₂ = 7.7 μC is located along the x-axis at a distance x₂ = 8.2 cm from q₁. Charge q₂ is displaced a distance y₂ = 3.1 cm in the positive y-direction.

We need to calculate the distance

Using Pythagorean theorem

$r=\sqrt{x_{2}^2+y_{2}^2}$