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2 years ago

Average human body temperature is 98.6°F. What is the equivalent in degrees Celsius?

Physics

1 answer:

Gala2k [10]2 years ago

6 0

37° Celsius is equal to 98.6° Fahrenheit

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How far is the region from the equator or helps control climate

alexira [117]

could you please specify?

4 0

2 years ago

Ann walked 1.5 miles south to her house in 0.5 hours. what is Ann's speed? what is Ann's velocity

ipn [44]

To calculate the speed and velocity of the Ann`s we use the formula,

$v= \frac{d}{t}$

Here, d is distance and t is time and v if we take it with direction then it is called velocity and if we take it without the direction then it is called speed.

Given $d=1.5 miles$ and $t=0.5 hours$ .

Substituting these values in above equation we get

$v=\frac{1.5mi }{0.5 h} = 3 mi/h$

As Ann walked towards south direction therefore, Ann`s velocity is 3 mi/h south and her speed is 3 mi/h .

7 0

3 years ago

A planet moves fastest in its orbit around the sun when it is at which position?

Nesterboy [21]

Answer:

When it's closest to the sun.

Explanation:

The force of gravity acting on a planet is equal to its mass times its centripetal acceleration.

Fg = m v^2 / r

The force of gravity is defined by Newton's law of universal gravitation as:

Fg = mMG / r^2

Therefore:

mMG / r^2 = m v^2 / r

MG / r = v^2

v increases as r decreases. So the planet is moving fastest when it's closest to the sun, also known as the <em>perihelion</em>.

6 0

3 years ago

Read 2 more answers

Light is shining perpendicularly on the surface of the earth with an intensity of 680 W/m^2. Assuming that all the photons in th

andrew11 [14]

Answer:

3.066×10^21 photons/(s.m^2)

Explanation:

The power per area is:

Power/A = (# of photons /t /A)×(energy / photon)

E/photons = h×c/(λ)

photons /t /A = (Power/A)×λ /(h×c)

photons /t /A = (P/A)×λ/(hc)

photons /t /A = (680)×(678×10^-9)/(6.63×10^-34)×(3×10^-8)

= 3.066×10^21

Therefore, the number of photons per second per square meter 3.066×10^21 photons/(s.m^2).

4 0

3 years ago

The latent heat of fusion for Aluminium is 3.97 x 105. How much energy would be required to melt 0.75 kg of it?

RoseWind [281]

Answer:

$E = 2.9775\times10^5 J$

Explanation:

Given: The latent heat of fusion for Aluminum is $L = 3.97\times10^5 J/Kg$

mass to be malted m = 0.75 Kg

Energy require to melt E = mL

$E = 3.97\times10^5\times0.75 = 2.9775\times10^5 J$

Therefore, energy required to melt 0.75 Kg aluminum

$E = 2.9775\times10^5 J$

5 0

2 years ago