Average human body temperature is 98.6°F. What is the equivalent in degrees Celsius?

Consider a positive charge Q and a point B twice as far away from Q as point A. What is the ratio of the electric field strength

Vikentia [17]

Answer:

$\frac{E_{A}}{E_{B}}=4$

Explanation:

The electric field is defined as the electric force per unit of charge, this is:

$E=\frac{F}{q}$ .

The electric force can be obtained through Coulomb's law, which states that the electric force between to electrically charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges. The electric force can be expressed as

$F=\frac{kQq}{r^{2}}$ .

By substitution we get that

$E=\frac{kQq}{qr^{2}}\\\\E=\frac{kQ}{r^{2}}$

Now, letting $E_{A}$ be the electric field at point A, letting $E_{B}$ be the electric field at point B, and letting R be the distance from the charge to A:

$E_{A}=\frac{kQ}{R^{2}}\\\\E_{B}=\frac{kQ}{(2R)^{2}}$ .

The ration of the electric fields is

$\frac{E_{A}}{E_{B}}=\frac{\frac{kQ}{R^{2}}}{\frac{kQ}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(4)R^{2}}}\\\\\\\frac{E_{A}}{E_{B}}=\frac{1}{\frac{1}{(4)}}\\\\\frac{E_{A}}{E_{B}}=4$

This means that at half the distance, the electric field is four times stronger.

4 0

3 years ago

The geologic force applied to rocks is called

amid [387]

The geologic force applied to rocks is called compression. Compression is the stress that squeezes rocks together. As a result of the compression rocks fold or fracture depending on their compressive strength or compression strength - the capacity of a material or structure to withstand loads tending to reduce size.
When the compression is horizontal the crust will be shortened and thickened. When the compression is vertical maximum a section of rock will fail in normal faults, horizontally extending and vertically thinning a given layer of rock.

4 0

3 years ago

1. A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts

Snezhnost [94]

Answer:

397 j

Explanation:

Because 5.0kg yuh

3 0

2 years ago

A 1.0-kilogram ball is dropped from the roof of a building 40. meters tall. What is the approximate time of fall? [Neglect air r

Effectus [21]

H = 40 m, the height from which the ball is dropped.
m = 1 kg, the mass of the ball

Assume g = 9.8 m/s² and neglect air resistance.

The initial vertical velocity is zero.
If t = the time of flight, then
40 m = (1/2)*g*(t s)² = 0.5*9.8*t²
t² = 40/4.9 = 8.1633
t = 2.857 s

Answer: 2.9 s (nearest tenth)

3 0

4 years ago

Read 2 more answers

A weightlifter must exert 25 Newtons of force to

kakasveta [241]

$Work=Force \: × \: displacement \\ => W=Fs \\ \\ Given, \\ Force=25 \: N \\ Displacement=2m \\ \\ so \: work = 25 \: N \: \times 2m \\ = > work = 25kgm {s}^{ - 2} \times 2m \\ = > work = 50kg {m}^{2} {s}^{ - 2} \\ = > work = 50J$

This is the answer.

Hope it helps!!

6 0

3 years ago