Answer:
0.45 m/s in the negative x-direction
Explanation:
From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum
Momentum, p=mv where m is the mass and v is the velocity
where is the common velocity, and are velocities of magnet moving in positive x-direction and magnet moving in negative x-direction respectively, and are masses of magnet moving in positive x-direction and magnet moving in negative x-direction respectively.
Substituting 125 g for and 85 g for , 7.33 m/s , -11.9 m/s for then
Therefore, the velocity of single unit is 0.45 m/s in the negative x-direction
Answer:
the speed acquired by the man is:
Explanation:
Use conservation of linear momentum to solve this problem, and make sure you start by converting the 63 g stone mass into kilograms = 0.063 kg.
Now from conservation of linear momentum, the momentum imparted to the stone (which is the product of the stone's mass time its speed) must equal in magnitude that of the 90 kg man. Then we need to find the unknown speed of the man:
therefore the speed acquired by the man is:
The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
<h3>What is force?</h3>
The force is an action of push or pull which makes a body to move or stop.
Given is the weight of tourist W = 805 N and L is the length of the bridge.
Let the reaction force at both the ends of the bridge is R1 and R2.
Taking the moments about point A,
R1 x 0 - W x L/4 +R2 x L =0
R2 = W/4
R2 = 805 /4
R2 = 201.25 N
Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.
Learn more about force.
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