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enyata [817]
3 years ago
12

Is nickel coin magnetic?

Physics
2 answers:
katen-ka-za [31]3 years ago
8 0

Answer:

Yes

Explanation:

Hey there!

Nickles are always magnetic. So it is the same for a nickle coin.

~I hope I helped you! :)~

Eddi Din [679]3 years ago
3 0
Yes ! The Coin is Magnetic. Try and experiment yourself , make sure a adult is around . Since 1992, coins have been made with steel, which is magnetic. (Pre-1992 coins are made out of bronze, which will not attract.) The dangling shows us how magnetic force travels through some metals, in this case coins (coins become magnetised when they attach) but gets weaker with each one



What the Video for more help : https://terpconnect.umd.edu/~wbreslyn/magnets/is-nickel-magnetic.html
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For each of the following pairs of gas properties, describe the relationship between the properties, describe a simple system th
asambeis [7]

Answer:

For  each pair of properties of a gas, the relationships are (see the explanation for the description of the systems):

  1. (a) Volume and pressure: The relationship between them is inversely proportional.
  2. (b) Pressure and temperature: They have a directly proportional relationship.
  3. (c) Volume and temperature: They relationship is directly proportional.
  4. (d) Number of gas particles and pressure: The relationship is directly proportional between them.

Explanation:

1. Volume and pressure (temperature and amount of particles constant):

They have an inversely proportional relationship, because <em>if volume is reduced, the pressure increases, or if the volume increases, the pressure decreases</em>.

A simple system could be one similar to the one used by Boyle to test this relationship:

  • Seal the short extreme of a translucent J tube. It could be glass or plastic.
  • Put some water on it. As much as needed to have both sides of the tube filled.
  • Using a syringe, and a flexible small tube,inject a determined volume of air in the bottom in a way that the bubble is trapped in the seal side of the J tube.
  • Then if more water is added to the tube, it will increase the pressure (from the pressure definition is possible to in the trapped air, and is possible to measure the compression of the air bubble. The same is possible if using the syringe, and the flexible tube, some water is removed, and the increasing of volume could be observed.

2. Pressure and temperature (volume and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure would increase, also</em>.

A simple system to show this is two cans of soda.

  • The can is rigid, so the volume is always constant, and the amount of gas inside the soda is the same.
  • Put one can under the sun, and the other in the cooler.
  • After a while, take it out the can in the cooler, and open both cans.
  • The one that was under the sun will "explode", in other words, it will liberate a lot of foam of gas and soda, meaning that the pressure inside the can was high.
  • The one that was in te cooler, won't liberate any foam, meaning that the pressure was low.

3. Volume and temperature (pressure and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure will increase, also</em>.

A simple system to show this is a party balloon.

  • Fill the party balloon with some air, not enough to be close to explode, but enough to have it of a medium size. Tie the filling hole of the balloon.
  • The air inside the balloon would be at the same pressure than the atmosphere around it, so always will be at this pressure, and the close hole ensure that it has always the same amount of air inside.
  • Now is possible to use some heat source, for example as a hair dryer to increase the temperature of the balloon and its contents. The size of the balloon will increase. Then using water is possible to cool it down and watch how its size decreases.

4. Number of gas particles and pressure (volume and temperature of gas remains constant)

They have a directly proportional relationship, because <em>if the amount of gas particles is reduced, the pressure decreases, or if quantity of gas particles increases, the pressure will increase, also</em>.

A simple system to show this would be a bicycle tire:

  • The tire is rigid, so its volume is essentially constant, and the temperature would remains the same if not moving or driving it.
  • Using a tire gauge, it is possible to know the manometric pressure inside the tire, that is the difference between the actual pressure inside the tire and the atmospheric pressure.
  • Then each time that using an air pump some air is injected in the tire, it si possible to check the pressure inside it using the gauge, and observe how is increasing.
  • Also, is possible to open the valve, to allow some air to escape, then use the gauge to observe how the pressure decreases.

7 0
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The area of an equilaterla triangle is increasing at a rate of 5 m^2/hr. find the rate at witch the height is chganging when the
Lena [83]

The rate at which the height is changing is ( 5 / x ) m / hr

We know that,

Area of an equilateral triangle A = \sqrt{3} x^{2} / 4

h = \sqrt{3} x / 2

Where,

x = Side

h = Height

Given that,

dA / dt = 5 m^{2} / hr

h = \sqrt{3} x / 2

Differentiate both sides with respect to t

dh / dt = ( \sqrt{3}  / 2 ) ( dx / dt )

dx / dt = ( 2 /  \sqrt{3} ) ( dh / dt )

A = \sqrt{3} x^{2} / 4

Differentiate both sides with respect to t

dA / dt = ( \sqrt{3} / 4 ) ( 2x ) ( dx / dt )

5 =  ( \sqrt{3} / 4 ) ( 2x ) ( 2 /  \sqrt{3} ) ( dh / dt )

dh / dt = ( 5 / x ) m / hr

Rate of change of height is defined as the rate at which height of an object changes with respect to time. It is represented as dh / dt

Therefore, the rate at which the height is changing is ( 5 / x ) m / hr

To know more about Rate of change of height

brainly.com/question/13283964

#SPJ4

6 0
1 year ago
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